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3 years ago

Please help me with this

Mathematics

1 answer:

Lunna [17]3 years ago

7 0

9514 1404 393

Answer:

(a) SSS

Step-by-step explanation:

Two of the sides are marked congruent, and the third side is shared (so is congruent to itself). The triangles are congruent by the Side-Side-Side (SSS) postulate.

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Masja [62]

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3 years ago

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vesna_86 [32]

Step-by-step explanation:

-3x + 7y = 5x + 2y (you subtract the 2y from both sides)

-3× + 5y = 5x (then add 3x to both sides)

5y = 8x (use x = - 5)

5y = 8x - 5 = -40 (both sides are divided by 5)

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3 years ago

-(y + 2) + 8 = 3 I’m so confused on this, please send help

Hoochie [10]

Don't be worried friend :)

-(y + 2) + 8 = 3

=> -(y + 2) = -5

=> y + 2 = 5

=> y = 3

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3 years ago

Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB

Digiron [165]

Answer: The distace between midpoints of AP and QB is $\frac{a}{8}$ .

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = $\frac{AP}{2}$

QB = $\frac{AP}{2}$

Substituing:

AP + 2*( $\frac{AP}{2}$ ) = a

2AP = a

AP = $\frac{a}{2}$

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = $\frac{AP}{2}$

QB = $\frac{a}{2}*\frac{1}{2}$

QB = $\frac{a}{4}$

MIdpoint is the point that divides the segment in half, so:

Midpoint of AP:

$\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}$

$\frac{AP}{2} = \frac{a}{4}$

Midpoint of QB:

$\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}$

$\frac{QB}{2} = \frac{a}{8}$

The distance is:

d = $\frac{a}{4} - \frac{a}{8}$

d = $\frac{a}{8}$

4 0

3 years ago

Use the information in the picture.

Katarina [22]

Yes, parallelogram congruent angles theorem

8 0

3 years ago