Question

Need some math help!

Answer 1

Angle A is 91°

In order to get to that answer, you have to remember your SOHCAHTOA method (Or Sin= Opp/Hyp Cos= Adj/Hyp and Tan= Opp/Adj)

So first try to find Angle C, you would use SOH. So Sin C = 7/14 (7 is your opposite and 14 is your hypotenuse) Which when you inverse Sin (or Sin^-1) the 7/14, in degrees, you should end up with 30°. Next do the same thing to Angle B but this time instead of 7/14, it's now gonna be Sin B= 12/14 (12 being opposite to B and 14 being the hypotenuse) and then you Inverse Sine (Or Sin^-1) the 12/14 and you should get 59°.

At this point, you should know basic angle solving skills. Which being Angle C + Angle B + Angle A = 180. Plug in the two you know, so 30+59+Angle A= 180

89+ Angle A = 180

180-89= 91°

Final solution: Angle A = 91°

Answer 2

This is a right triangle, the measure of angle A is 90 degrees.

First thing to do I guess is finding B and C.

tan^-1 (7/12) = 30 degrees

tan^-1 (12/7) = 60 degrees

60 + 30 = 90

180 - 90 = 90. Therefore angle A = 90 degrees