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Aleksandr [31]
3 years ago
15

Point x is at 2/3 on a number line. On the same number line, point y is at the same distance from 0 as a point x, but has a nume

rator of 8 . What is the denominator of the fraction at point y? Draw a number line to model the problem

Mathematics
1 answer:
BaLLatris [955]3 years ago
7 0

Answer:

<em>The denominator is 12</em>

\displaystyle y=-\frac{8}{12}

Step-by-step explanation:

<u>The Number Line</u>

We can represent any real number in a properly segmented line, where the zero-mark is the separation between positive numbers to its right side and negative numbers to the left side.

We are given the number x = 2/3. Since it's positive, its location lies to the right of the zero but before the 1 as shown in the figure below.

We want to locate a second point y at the same distance from 0 as the point x, so we have two options: y is the same as x, or y is negative at the same distance from zero. We chose the last option.

Its numerator must be 8, so we need to multiply it by 4. But we cannot alter the value of x, so we must also multiply the denominator by 4, which gives us the fraction 8/12, but recall it must be negative.  

\boxed{\displaystyle y=-\frac{8}{12}}

The denominator is 12

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In the Angle Measures of Polygons section, the sum of the exterior angles of a polygon is always _______ degrees. *
den301095 [7]
It’s 360 degrees. The measure of one exterior angle is equal to 360 divided by the number of sides in the polygon
5 0
4 years ago
Explain how to use the coordinates and absolute value to find the distance between points at (3, –7) and (3, 2).
ser-zykov [4K]

Answer:

Using the formula for the distance between two points, which is generated using coordinates and absolute value, we find that the distance between these two points is of 9 units.

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

This formula is generated using coordinates and absolute value.

In this question:

(3,-7) and (3,2). So

D = \sqrt{(3-3)^2+(2-(7))^2} = \sqrt{81} = 9

The distance between these two points is of 9 units.

4 0
3 years ago
HURRY!! PLEASE!!
Marina86 [1]

Answer:

c. y=56(2)x-1 sorry if its wrong

4 0
4 years ago
!!please, please help me!!
grigory [225]

Answer:

Length: 12

Width: 2\sqrt{10\\}

Area: 24\sqrt{10\\}

Step-by-step explanation:

We first find the points of C and D to find the length.

C: (-4,-5)

D: (2,-3)

The distance is 2\sqrt{10\\.

Now for the height.

A: (2,9)

D: (2,-3)

The distance is 12.

Area: 2\sqrt{10\\×12 = 24\sqrt{10\\}

6 0
3 years ago
In a​ region, 90​% of the population have brown eyes. If 15 people are randomly​ selected, find the probability that at least 13
Andrew [12]

Answer:

a) P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)

P(X=13)=(15C13)(0.9)^{13} (1-0.9)^{15-13}=0.267  

P(X=14)=(15C14)(0.9)^{14} (1-0.9)^{15-14}=0.343  

P(X=15)=(15C15)(0.9)^{15} (1-0.9)^{15-15}=0.206  

And replacing we got:

P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)=0.267+0.343+0.206=0.816

b) D. No​, because the probability of this occurring is not small.

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Part a

If 15 people are randomly​ selected, find the probability that at least 13 of them have brown eyes.

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.90)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want to find this probability:

P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)

P(X=13)=(15C13)(0.9)^{13} (1-0.9)^{15-13}=0.267  

P(X=14)=(15C14)(0.9)^{14} (1-0.9)^{15-14}=0.343  

P(X=15)=(15C15)(0.9)^{15} (1-0.9)^{15-15}=0.206  

And replacing we got:

P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)=0.267+0.343+0.206=0.816

Part b

Is it unusual to randomly select 15 people and find that at least 13 of them have brown​ eyes? Note that a small probability is one that is less than 0.05.

Since our calculated probability is too higher compared to 0.05 we can conclude this:

D. No​, because the probability of this occurring is not small.

7 0
4 years ago
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