There are two ways to work this out: normal variables or using "imaginary" numbers.
Normal variables:
![(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}](https://tex.z-dn.net/?f=%20%287%2B2i%29%283-i%29%5C%5C%287%2A3%29%2B%5B7%2A%28-i%29%5D%2B%283%2A2i%29%2B%5B2i%2A%28-i%29%5D%5C%5C21-7i%2B6i-2i%5E%7B2%7D%5C%5C%5C%5C21-i-2i%5E%7B2%7D)
Imaginary numbers:
Using the result from earlier:

Now since

, then the expression becomes:
You can use the sum and difference identities which for cosine is cos(a+b)= cosacosb-sinasinb
Answer: $7,500
Step-by-step explanation:
Use the formula: SI = P(1 + rt)
SI = 5000(1 + 0.05[10])
SI = 5000 + 2500
SI = $7,500
After 10 years, your balance should be $7,500
Answer:
When a line gets closer to a horizontal asymptote, the the y value decreases, but the y value is never equals the value of the asymptote
Step-by-step explanation:
^
A scale is a term that refers to the <em>representative fraction</em> for comparing the <u>original</u> length and <u>image</u> length of a given <u>object</u>. It means implies that every 1 unit on the <u>drawing</u> is equal to <u>100</u> units on the <u>park</u>.
A <em>scale</em> is a term that can be referred to as the <em>representative fraction</em> that compares the <u>original</u> length and <u>image</u> length of a given <em>object</em>. Types of <u>scale</u> include enlarged scale, reduced scale, and real scale.
- Enlarged scale is a <u>scale</u> that is used when the <u>size</u> of a given <em>object</em> is to be <em>increased</em>.
- <em>Reduced scale</em> is used when the <u>size</u> of a given <u>object</u> is to be <em>decreased</em>.
- <u>Real scale</u> implies the <em>exact size</em> of a given <u>object</u>.
<u>Scale</u> can be expressed as;
Scale = 
Thus a <em>scale</em> has no unit.
Therefore, the given question <em>implies</em> that every 1 unit on the <u>drawing</u> is equal to 100 units on the <u>original</u> park. Thus it is a <em>reduced scale</em>.
For more clarifications on a scale drawing, visit: brainly.com/question/23209981
#SPJ1