I believe the correct answer is B
Answer:
The center is at (0,0)
The vertices are at ( (
±2 sqrt(2),0)
foci are (
±sqrt(5),0)
Step-by-step explanation:
3x^2 + 8y^2 = 24
Divide each side by 24
3x^2 /24 + 8y^2/24 = 24/24
x^2/8 + y^2 /3 = 1
The general equation of an ellipse is
(x-h)^2/ a^2 + (y-k)^2 / b^2 = 1
a>b (h,k) is the center
the coordinates of the vertices are (
±a,0)
the coordinates of the foci are (
±c,0), where ^c2=a^2−b^
2
The center is at (0,0)
a = sqrt(8) = 2sqrt(2)
The vertices are at ( (
±2 sqrt(2),0)
c = 8 - 3 =5
foci are (
±sqrt(5),0)
Answer:
Step-by-step explanation:
1). By applying Pythagoras theorem in the triangle formed by two sides and the diagonal,
Length of the diagonal = 
= 
= 25√2
AC ≈ 35.56 units
2). Since, diagonal of a square is the angle bisector of interior angles of the square,
m∠CAB = 45°
By applying sine rule in ΔABC,
sin(45°) = 
AC = 25√2
AC ≈ 35.56 units
Your answer is C) Translation
I don’t know the answer to this sorry
