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BlackZzzverrR [31]

3 years ago

9

Find the distance between X (5, 7) and Y (-6, 6). Round answer to the nearest tenth.

1 answer:

JulsSmile [24]3 years ago

4 0

Answer: 11.0 or 11

Step-by-step explanation:

To find the distance first find the difference between the coordinates. find the change in the x and y coordinates and square them to add them to get a number and find the square root of that same number to find the distance.

x coordinates: 5-(-6)= 11

y coordinate: 7-6 = -1

Now square them

11^2 + 1^2 = l^2 where l is the distance

121 + 1 = l^2

122 =l^2

l = $\sqrt{122}$

l = 11.045 Rounded to the nearest tenth is 11.0

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Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. W

Travka [436]

Complete question:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A double prime B double prime?

A) segment a double prime b double prime = segment ab over 2

B) segment ab = segment a double prime b double prime over 2

C) segment ab over segment a double prime b double prime = one half

D) segment a double prime b double prime over segment ab = 2

Answer:

A) segment a double prime b double prime = segment ab over 2.

It can be rewritten as:

$A"B" = \frac{AB}{2}$

Step-by-step explanation:

Here, we are given triangle A″B″C which was formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin.

We know segment A"B" equals segment AB multiplied by the scale factor.

A"B" = AB * s.f.

Since we are given a scale factor of ½

Therefore,

$A"B" = AB * \frac{1}{2}$

$A"B" = \frac{AB}{2}$

The equation that explains the relationship between segment AB and segment A"B" is

$A"B" = \frac{AB}{2}$

Option A is correct

5 0

3 years ago

JulijaS [17]

Answer:

Small one is 4ft larger one is 12ft

4 0

2 years ago

Read 2 more answers

Len [333]

Answer:

isp2odbskoxnxndkekjrhsbnzmcnfjhdhdhhdhdhshjsh

7 0

3 years ago

Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x

Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

$(x-h)^2+(y-k)^2=r^2$

Where the point (h,k) is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

$x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121$

Add 10x to both sides:

$x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121$

Make two groups for variable "x" and variable "y":

$(x^2+10x)+(y^2-20y)=-121$

Complete the square:

Add $(\frac{10}{2})^2=5^2$ inside the parentheses of "x".

Add $(\frac{20}{2})^2=10^2$ inside the parentheses of "y".

Add $5^2$ and $10^2$ to the right side of the equation.

Then:

$(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4$

Rewriting, you get that the equation of the circle in center-radius form is:

$(x+5)^2+(y-10)^2=2^2$

You can observe that the radius of the circle is:

$r=2$

And the center is:

$(h,k)=(-5,10)$

6 0

3 years ago

Read 2 more answers

Twice a certain whole number subtracted from 3 times the square of the number leaves 133. Find the number

user100 [1]

Answer:

7

Step-by-step explanation:

"a certain whole number" is a number that we don't know, so pick a variable, let's use n

"Twice" means two times, so we'll use 2n for this.

"subtracted from" means the 2n will be AFTER the minus sign.

____ - 2n

What goes in front? "3 times the square of the number" 3n^2

Now we have 3n^2 - 2n

Lastly, we see the result is 133. So this gives us:

3n^2 - 2n = 133 To solve, subtract 133 from both sides of the equation.

3n^2 -2n - 133 = 0 Next FACTOR.

(3n + 19)(n - 7) = 0

3n+19=0 and n-7=0

n=-19/3 and n=7

Since we are looking for a whole number choose n=7

6 0

3 years ago