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4 years ago

7y + 4x + 4 - 2x + 8 what is the constant

Mathematics

1 answer:

N76 [4]4 years ago

3 0

4 and 8::::::: because they have no variable u can add 4 and 8 which would be 12

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Tomas has $45.00 to purchase favors for a party. If the favors are $3.75 each, how many favors can Tomas buy?

ludmilkaskok [199]

Answer: 12

Step-by-step explanation:

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3 years ago

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Find the rate of change of the following table.

Serjik [45]

Answer:

$\frac{1}{3}$

Step-by-step explanation:

The rate of change is measured by the slope of the line in this linear table.

Calculate the slope m using the slope formula

m = $\frac{y_{3}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 3, 0) and (x₂, y₂ ) = (3, 2) ← 2 ordered pairs from the table

m = $\frac{2-0}{3+3}$ = $\frac{2}{6}$ = $\frac{1}{3}$ ← rate of change

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3 years ago

What is 6 1/2-(1 7/8)=?

kozerog [31]

$\frac{37}{8}$
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7 0

4 years ago

Read 2 more answers

Evaluate the limits<br><br>

julsineya [31]

$x > \ln(x)$ for all $x$ , so

$\displaystyle \lim_{x\to\infty} (\ln(x) - x) = - \lim_{x\to\infty} x = \boxed{-\infty}$

Similarly, $\displaystyle \lim_{x\to\infty} (x-e^x) = - \lim_{x\to\infty} e^x = \boxed{-\infty}$

We can of course see the limits are identical by replacing $x\mapsto e^x$ , so that

$\displaystyle \lim_{x\to\infty} (\ln(x) - x) = \lim_{x\to\infty} (\ln(e^x) - e^x) = \lim_{x\to\infty} (x - e^x)$

You can also rewrite the limands to accommodate the application of l'Hôpital's rule. For instance,

$\displaystyle \lim_{x\to\infty} (x - e^x) = \ln\left(\exp\left(\lim_{x\to\infty} (x - e^x)\right)\right) = \ln\left(\lim_{x\to\infty} e^{x-e^x}\right) = \ln\left(\lim_{x\to\infty} \frac{e^x}{e^{e^x}}\right)$

Using the rule, the limit here is

$\displaystyle \lim_{x\to\infty} \frac{(e^x)'}{\left(e^{e^x}\right)'} = \lim_{x\to\infty} \frac{e^x}{e^x e^{e^x}} = \lim_{x\to\infty} \frac1{e^{e^x}} = 0$

so the overall limit is

$\displaystyle \lim_{x\to\infty} (x - e^x) = \ln\left(\lim_{x\to\infty} \frac{e^x}{e^{e^x}}\right) = \ln(0) = \lim_{x\to0^+} \ln(x) = -\infty$

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2 years ago

odness-of-fit test where all assumptions were met yielded the chi-square test statistic χ2=1.92 and a corresponding p-value of 0

mojhsa [17]

Answer: hello the options related to your question is missing attached below are the options

answer : The researcher did not state that the p-value is conditional on the null hypothesis being true ( A )

Step-by-step explanation:

What is wrong with the researcher's interpretation is that the researcher did not state that the p-value is conditional on the null hypothesis being true.

The P-value is a required value when either rejecting or accepting the null hypothesis. and the researcher did not add the clause that the probability of getting a statistic > 1.92 provided the null hypothesis is assumed to be true

4 0

3 years ago