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Scilla [17]
3 years ago
15

7y + 4x + 4 - 2x + 8 what is the constant

Mathematics
1 answer:
N76 [4]3 years ago
3 0
4 and 8::::::: because they have no variable u can add 4 and 8 which would be 12
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12 7/8 − (1 1/7 +3 1/2 )∙(2−1 3/7 )=<br><br> I WILL GIVE 30 points!
podryga [215]

Answer: 12446/545← in fraction form. But in decimal form it's 22.83670.

Step-by-step explanation:

*Hopefully this helps:) Mark me the brainliest:)!!!

8 0
3 years ago
Can someone plz answer this not in decimals <br> 17 divided by 1,569
nordsb [41]

Answer:

in fraction from it is \frac{17}{1569}

Step-by-step explanation:

7 0
3 years ago
A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0
3 years ago
Data were collected on the number of days per week that members visit a certain fitness center. The values varied from 0 to 7, a
pshichka [43]

Answer:

D

Step-by-step explanation:

choice A is not guaranteed since the values varied from 0 to 7.

choice B seems alright, but doesn't include about or anything about the long run.

choice C is incorrect because 50% are less than 3.12 and 50% are greater than 3.12.

choice D seems pretty good, since it says average, long run, approach, etc.

choice E is incorrect because it says "will be". It is not definite.

8 0
3 years ago
What is the slope of the line that passes through the points(7,-9) and (15,-29)?
Alex Ar [27]
(Y-Y1)/(X-X1)
(-9-(-29))/(7-15)
20/-8
-2 1/2
The slope is -2 1/2
3 0
2 years ago
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