Vector QP= (-5+6, 11-4) = (1, 7)
its magnitude is QP= sqrt( 1 + 49)= sqrt (50)=5sqrt2
Answer:
Vertex
Step-by-step explanation:
Answer:
12353
Step-by-step explanation:
123
Step-by-step explanation:
a) The rule is <em><u>multiply the previous term by 6 then add 13</u></em>. So if the 1st term is n0 = -2, then the next term n1 is
n1 = 6n0 + 13
= 6(-2) + 13
= 1
n2 = 6n1 + 13
= 6(1) + 13
= 19
So the sequence goes like
-2, 1, 19
b) Now the sequence is reversed so let's write the terms as follows:
19, 1, -2
The new rule now is <em><u>subtract</u></em><em><u> </u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>then</u></em><em><u> </u></em><em><u>divide</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>6</u></em><em><u>.</u></em> You can check this as follows:
n0 = 19
n1 = (n0 - 13)/6
= (19 - 13)/6
= 1
n2 = (n1 - 13)/6
= (1 - 13)/6
= -2
Answer:
9.434 units
Step-by-step explanation:
Given data
points (5,4) and (-3,-1)
x1= 5
y1= 4
x2= -3
y2= -1
The expression for the distance between two points is
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((-3-5)²+(-1-4)²)
d=√((-8)²+(-5)²)
d=√64+25
d=√89
d=9.4339
d= 9.434 units
Hence the distance between the points is 9.434 units
