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MakcuM [25]
3 years ago
14

-4(2x-3)>-28 please i need this result

Mathematics
1 answer:
Len [333]3 years ago
3 0

-4 (2x - 3) > -28

Divide by -4 on both sides. Since we're dividing by a negative, we need to switch the sign.

2x - 3 < 7

Add 3 to both sides

2x < 10

Divide by 2 on both sides

x < 5

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RectangleABCD has vertices at A(– 3, 1),B(– 2, – 1),C(2, 1), andD(1, 3). What is the area, in square units, of this rectangle? A
Anna [14]

Answer:

Option A. 10\ units^{2}

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

we have

A(-3,1),B(-2,-1),C(2,1),D(1,3)

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

<em>Find the distance AD</em>

A(-3,1),D(1,3)

substitute in the formula

AD=\sqrt{(3-1)^{2}+(1+3)^{2}}

AD=\sqrt{(2)^{2}+(4)^{2}}

AD=\sqrt{20}

AD=2\sqrt{5}\ units

<em>Find the distance AB</em>

A(-3,1),B(-2,-1)

substitute in the formula

AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}

AB=\sqrt{(-2)^{2}+(1)^{2}}

AB=\sqrt{5}

AB=\sqrt{5}\ units

Find the area

A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}

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Step-by-step explanation:

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