Find the ratio of height to shadow on the pole. It will be similar to the ratio of height to shadow length on the tower if it's the same time of day.
Solve
Answer:
ORDER THEM FROM LEAST TO GREATEST THEN CROSS OFF A NUMBER FROM EACH SIDE TILL YOU ARE LEFT WITH ONE IN THE MIDDLE
ANSWER IS 17
Step-by-step explanation:
<em>parallelogram</em>
1. perimeter 10(2)+10(2)=32+20
perimeter = 52cm
area=b times h
area = 16(9)=144cm2
2 <em>TRAPEZOID</em>
<em> </em>perimeter =( 21+24+25+44.67)m
=114.67m
area= 1/2( b1+b2)h
1/2(44.67+25)20
696.7m2
3. perimeter = 2+3+12+2+3+5+3+2+9+7+3
=51<u>cm</u>
area = 54+6+6+6=72cm2<u> </u>
4. perimeter is 10+4+2+3+ 2+4+10+23 = <u>58cm</u>
<u>area is </u>
(11+23).8=37.8
=272
trap-rect=136-6
<em>=130ft2</em>
Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
16 on the top and 4 on the bottom
