Answer:
<u>Solution</u><u> </u><u>given</u><u>:</u>
<u>one</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u> </u><u>must</u><u> </u><u>be</u><u> </u><u>less</u><u> </u><u>than</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>of</u><u> </u><u>two</u><u> </u><u>other</u><u> </u><u>side</u><u> </u><u>.</u>
<u>by</u><u> </u><u>making</u><u> </u><u>these</u><u> </u><u>sense</u><u>:</u>
3<10+20
10<20+3
20<10+3not true
these three side are not possible.
again
10<20+25
20<25+10
25<20+10
these three side are true so
required side are:
Side 1:10
Side 2:25
Side 3:20
Answer:
yes i agree
Step-by-step explanation:
easier way is .25x60
Answer:

Step-by-step explanation:
Given 
To make A as the subject of the formula we need to rearrange
Divide by
throughout we get


WELL 22.5/32 is 70% so to just get that you need to get roughly 9.5 questons wrong
Area is pi r squared=201.06
R squared=201.06/pi
R=square root of 201.06/pi
D=2(square root of 201.06/pi)
Pi d=circumference
Answer=50.265