Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :
Now , second derivative :
( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .
2(x - 4) + 7(x + 2)
mutiply the first bracket by 2
(2)(x)=2x
(2)(-4)= -8
mutiply the second bracket by 7
(7)(x)=7x
(7)(2)= 14x
2x-8+7x+14
2x+7x-8+14 ( combine like terms)
Answer:
9x+6 or 6+9x
The answer to this question is x equals 5
Answer:
y=3x+1
Step-by-step explanation:
I'm very bad at explaining things so im sorry if this doesn't make any sense
the y axis goes up
the x axis goes sideways
to fill in the "y = ____x+_____"
you find a point on the line, see how far up it is from 0,0 and put that in the first blank space, in this case its 3. then you find how much it goes over on the x axis. in this case its 1 over. so you would put 1.
