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3 years ago

Let f(x) = 3x + 5

Mathematics

1 answer:

sashaice [31]3 years ago

4 0

The answer is C, -7 because:

f(x)=3(-4)+5=-7
F(x)=-4(-4)+7=-7

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the equation of a wave is given as y=0.5sin(3πx + 50πt). when x and y are in metres and t is in seconds. Find the amplitude, the

Crazy boy [7]

if they are optional

all are correct

<h3>step by step instructions:</h3>

Correct option is

All are correct

the equation of a given progressive wave is

y=5sin(100πt−0.4πx) ......(i)

The standard equation of a progressive wave is

y=asin(ωt−Kx) ...(ii)

Comparing (i) and (ii), we get

a=5m,ω=100π rad s

−1

,k=o.4πm

−1

도움이 되기를 바랍니다. :)

좋은 하루 되세요 :)

가장 똑똑한 것으로 표시 :)

4 0

3 years ago

Find a vector b if:<br> It has the same direction as 2,-1<br>and has<br>length of 3 units

Gnom [1K]

Answer:

I dunno just need the points sorry

Step-by-step explanation:

7 0

3 years ago

Suppose that the commuting time on a particular train is uniformly distributed between 42 and 52 minutes. Bold a. What is the pr

nikdorinn [45]

Answer: 0.2

Step-by-step explanation:

Given: The commuting time on a particular train is uniformly distributed over the interval (42,52).

∴ The probability density function of X will be :-

$f(x)=\dfrac{1}{b-a}\\\\=\dfrac{1}{52-42}=\dfrac{1}{10}, 42$

Thus, the required probability :-

$P(X$

Hence, the probability that the commuting time will be less than 44 minutes= 0.2

7 0

3 years ago

~[~p\/(r/\~s)] true or false

viktelen [127]

false

20 more characters

7 0

3 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

3 years ago