Notice that 25+23+17+14+12+9=100, so among these students there are no 2 studying 2 subjects.
The probabilities of selecting students studying a certain subject are as follows
P(physics)=25/100
P(chemistry)=17/100
P(maths)=9/100
P(sociology)=23/100
P(political sciences)=14/100
P(anthropology)=12/100
since all the sets are disjoint, that is there are no common elements, and since all the students in consideration are enrolled in one these 6 subjects:
P(physics)+P(chemistry)+P(maths)+P(sociology)+P(political sciences)
+P(anthropology)=1
P(a)=P(sociology)+P(political sciences)+P(anthropology)+P(physics)
thus
P(a')=1-P(a)=P(chemistry)+P(maths)=17/100+9/100=26/100=0.26
Answer: 0.26
Answer:
23 of 8
23/8
23-8 is that it? it seems like something I did in class
Answer: 66,667 people
Step-by-step explanation:
The first thing is to find the area of the rectangle , since it is a rectangular field.
A = L X B
A = 500 X 600
A = 300,000
It was said that each person occupies 4.5 square feet , then to find the crowd we have:
Number of crowd = Area of the field / feet occupied by each person
= 300,000/4.5
= 66,666.66667
= 66, 667 to the nearest whole number
A. x > -16
46/-3=16
and because you're dividing by a negative number you have to flip the sign
