<span>X+2a = 16+aX-6a
8X - 16 = aX-2a
8(X-2) = a(X-2)
</span><span>(X-2)/<span>(X-2)</span> = a/8
1 = a/8
a= 8
</span>
Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula

where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,

or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
Step-by-step explanation:
street never meet
I believe the answer is:
y+18 = (-52/3)(x-3) in point slope form
Let me know if you need an explanation. Hope this helps.