Volume of a cylinder = π r² h
Let us assume the following values:
radius = 9
height = 10
Volume = 3.14 * 9² * 10
= 3.14 * 81 *10
Volume = 2,543.40
Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40
Volume = π r² h
= 3.14 * 2² * 40
= 3.14 * 4 * 40
Volume = 502.40
Original volume = 2543.40 V.S. Volume after change = 502.40
The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times.
Answer:
<h3>Sv is angle bisector of rst.</h3>
Step-by-step explanation:
2x = y-10
Rewrite as: 2x + 10 = y
Therefore:
2x+10 = y
2x +7 = 2y
Subtract the equations:
2x + 10 = y
- 2x + 7 = 2y
______________
3 = -y
Therefore y = -3
Substiture y = -3 into the second equation:
2x + 7 = 2(-3)
2x + 7 = -6
2x = -13
x= -6.5
Answer : (-6.5, -3)
The other endpoint is (1, -17).
The midpoint formula is:

Using our midpoint and endpoint, we have:

For the first equation (to find the x-coordinate) we will multiply both sides by 2:

Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
1 = x₂
For the second equation (the y-coordinate) we multiply both sides by 2:

Add 5 to both sides:
-22+5 = -5+y₂ + 5
-17 = y₂
This means that (x₂, y₂) is at (1, -17).
<span>2/3 (x-7)= -2
x - 7 = -2 * 3/2
x - 7 = -3
x = -3 + 7
x = 4</span>