B,
P(A and B)= P(A)xP(B)
P(A and B)=0.60x0.30
P(A and B)=0.18
Answer:
Explanation:
A. The minimum possible length of the rug is 1.
B. The maximum area of the rug is 2m^2
6.7 5 n
More than means +
Product of means •
So 6.7+(5n)
Answer:
Here we can use the relationship:
Distance = time*speed.
When Jose walks, his speed is 4 mph.
Then if he walks for X hours, the distance that he will travel is:
D = 4mph*X
When Jose runs, his speed is 8mph.
Then if he runs for T hours, the distance that he will travel is:
D´ = 8mph*Y
And we know that he travels in total 20 miles, then we must have that:
D + D´= 20mi
This leads to:
4mph*X + 8mph*Y = 20mi
Where X is the time that he walked, and Y is the time that he runed.
Then the equation that represents the different amounts of times that Jose runs and walks is:
4mph*X + 8mph*Y = 20mi
Where we can not really find the solutions for Y and X, because there is only one equation and two variables.
Answer:
Step-by-step explanation:
Given that fish length X is having the normal distribution for which the mean is 9 inches and the standard deviation is 2 inches.
X : N(9,2)
A) 
B) Here sample size = 300
Out of 300 fish we can expect 300(0.3085) to be shorter
i.e. 92.55=93 fish
