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3 years ago

REALLY NEED HELP: given that (-5,-2) is on the graph of f(x) find the corresponding point for the function 2f(x)

Mathematics

2 answers:

laiz [17]3 years ago

6 0

we are given

point for f(x) is (-5,-2)

Whenever we need to find point for a*f(x) , we will multiply a by y-value

Here , we have 2f(x)

so, we will multiply 2 units to y-value

y-value is -2

new y-value will be 2*-2=-4

so,

point for 2f(x) will be (-5,-4)........Answer

Inessa05 [86]3 years ago

5 0

point for f(x) is (-5,-2) multiply a by y-value. we have 2f(x). so, we will multiply 2 units to y-value. y-value is -2. new y-value will be 2*-2=-4 so, point for 2f(x) will be (-5,-4)........Answer we are given point for f(x) is (-5,-2)

Whenever we need to find point for a*f(x) , we will multiply a by y-value

Here , we have 2f(x)

so, we will multiply 2 units to y-value

y-value is -2

new y-value will be 2*-2=-4

so, point for 2f(x) will be (-5,-4). Hope this helped!

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A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

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3 years ago

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Mars2501 [29]

Put the value of x = 6 to the eqpression 5x² + x - 7:

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<h3>Answer: 179</h3>

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4 years ago

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slava [35]

Answer:

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Step-by-step explanation:

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3 years ago

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a small jet can fly 1,435 miles in 5 hours with a tailwind but only 1,215 miles in 5 hours into a headwind. find the speed of th

Ne4ueva [31]

Answer:

Speed of Jet in Still Air = 265 miles per hour

Speed of Wind = 22 miles per hour

Step-by-step explanation:

Let x be speed of jet

and c be speed of wind

We know D = RT, where

D is distance

R is rate

T is time

For first leg:

1435 miles in 5 hours, the rate is:

Rate = 287 mph

For second leg:

1215 miles in 5 hours, the rate is:

Rate = 243 mph

So 287 is with wind and 243 against wind, thus we can write:

x + c = 287

x - c = 243

Adding gives us:

2x = 530

x = 265 miles per hour [still rate]

Speed of wind:

x + c = 287

265 + c = 287

c = 22 miles per hour [speed of wind]

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