-8 (is less than or equal to) x ( which is less than) 3
Or [-8,3)
Answer:
see below
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h
We know the radius is 9 and the height is 20
V = pi ( 9)^2 ( 20)
V = 1620 pi
If we approximate pi by 3.14
V =5086.80 cm^3
If we approximate pi by pi button
V =5089.3800099 cm^3
Answer:
Step-by-step explanation:
5/1
Answer:
.
See the diagram attached below.
Let the chords be AB and AC with common point A.
AD is the diameter. Join B with D and C with D to form two triangles.
We need to prove that AB=AC.
\begin{gathered}In\ \triangle ABD\ and \triangle ACD;\\Given\ that\ \angle BAD=\angle CAD----(condition\ 1)\\since\ AD\ is\ diameter, \angle ABD=\angle ACD = 90^0\\So\ \angle ADB=\angle ADC--------(condition\ 2)\\AD=AD\ (common\ side)-----(condition\ 3)\\ \\So\ the\ triangles\ are\ congruent\ by\ ASA\ rule.\\Hence\ AB=AC.\end{gathered}
In △ABD and△ACD;
Given that ∠BAD=∠CAD−−−−(condition 1)
since AD is diameter,∠ABD=∠ACD=90
0
So ∠ADB=∠ADC−−−−−−−−(condition 2)
AD=AD (common side)−−−−−(condition 3)
So the triangles are congruent by ASA rule.
Hence AB=AC.
Answer: The equation is f(x) =
;
The piece of plastic has to have 10mm of thickness.
Step-by-step explanation: It is known that with 1 mm of thickness, 5% of the intensity is reduced. So, 95% of the light is transmitted.
For each milimetre added, "more" 95% of light is transmitted.
For example, if another milimetre of plastic is added, another 0.95 of light is transmitted:
0.95.0.95 = 0.9025 of light reach the visor
So, the model that relate thickness of plastic and intensity of light is:
f(x) = 
in which:
f(x) is the intensity of light;
x is thickness in mm;
Using the equation, the thickness necessary to reduce intensity to 60% is:
f(x) = 
0.6 = 
log 0.6 = log 
x. log (0.95) = log (0.6)
x = 
x = 9.95
x ≈ 10
The thickness necessary to reduce intensity of light to 60% is 10mm.