What is the expression in simplest radical form?<br> 4V90

<img src="https://tex.z-dn.net/?f=%5Ctext%7BI%20was%20eating%20cookies%20and%20had%20some%20thoughts.%20If%20I%20wanted%20to%20c

andrew-mc [135]

In the attachement, there is what I came up with so far. I think that finding 'a' is non-trivial, if possible at all.

$A_c$ - the area of a circle

$A_{cs}$ - the area of a circular segment

5 0

3 years ago

Maggie has a food scale with a digital display that shows the weight as a decimal number. The recipe she is using calls for ingr

strojnjashka [21]

Put the decimal over 100 and get rid of the decimal

8 0

3 years ago

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Lubov Fominskaja [6]

Answer:

okay let's start

Step-by-step explanation:

$use \: sine \: rule \\ \frac{x}{ \sin(31) } = \frac{42}{ \sin(59) } \: \: taking \: angle \: at \: c \: as \: 90 \\ x = \frac{ 42 \sin(31)}{ \sin(59)} \\ x = 25.236146$

3 0

2 years ago

A cookie factory monitored the number of broken cookies per pack yesterday.

trapecia [35]

Answer:

Confidence Interval - 2.290 < S < 2.965

Step-by-step explanation:

Complete question

A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.

Solution

Given

n=50

x=23.33

s=2.6

Alpha = 1-0.80 = 0.20

X^2(a/2,n-1) = X^2(0.10, 49) = 63.17

sqrt(63.17) = 7.948

X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69

sqrt(37.69) = 6.139

s*sqrt(n-1) = 18.2

$s\sqrt{\frac{n-1}{X^2 _{(n-1), \frac{\alpha }{2} } }$ $\leq \sigma \leq s\sqrt{\frac{n-1}{X^2 _{(n-1), 1-\frac{\alpha }{2} } }$

confidence interval:

(18.2/7.948) < S < (18.2/6.139)

2.290 < S < 2.965

8 0

3 years ago

please help!! Drag each pair of equations to show whether the system has no solution, one solution, or infinitely many solutions

Vanyuwa [196]

For the given system of equations, considering different systems are split by ;, we have that:

No solutions: 3y = x + 2, 9y = 3x + 7; y = 2x + 3, y = 2x + 5

One solution: 2y = 3x, -5y = -10x,; x = 6, y = 9.

Infinitely many solutions: y = 5x + 2, 3y = 15x + 6.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

It's equations can be written in the format:

Ax = b

Using the above format, we have that:

If A is different from zero, the system has one solution.

If A is zero and B is different of zero, the system has no solutions.

If both are zero, the system has infinite solutions.

At the first system, multiplying the first equation by -3 and adding with the second, we end up with:

0y = 0x + 2

0 = -2

Which is a false statement, hence it has no solutions.

At the second system, the equations are multiples, hence it has infinite solutions.

At the third system, the coefficients are not zero and are not multiples, and it has one solution.

In the fourth system, the one solution is already given.

At the fifth system, we have that:

2x + 3 = 2x + 5

0x = 2

Hence no solutions.

To learn more about system of equations, you can take a look at brainly.com/question/24342899

5 0

2 years ago

What is the expression in simplest radical form? 4V90