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Serhud [2]
4 years ago
12

Help please thank you

Mathematics
1 answer:
kozerog [31]4 years ago
4 0
To solve this question, we can use the tangent. The adjacent leg to the angle will have a length of 9.3 and the opposite leg will have a length of 7.4

Using these, we can create an equation to solve for unknown angle (let it be x) using the tangent.

\tan(x)=\dfrac{7.4}{9.3}

Take the inverse tangent, or arc tangent, on both sides.

x=tan^{-1}(\dfrac{7.4}{9.3})
\approx 39

Your answer is the first choice. I hope this helps! :)
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Plz Help more than one !!!!!!!!!!!!!!!!!!
jok3333 [9.3K]

Answer:

The correct option is (b).

Step-by-step explanation:

We need to find the equivalent to -2(4-3x)+(5x-2)

Using the associative property,

-2(4-3x) = -2(4)+2(3x)

= -8+6x

So,

-2(4-3x)+(5x-2) = -8+6x +5x-2

taking like terms together,

-2(4-3x)+(5x-2) = 6x+5x-8-2

= 11x-10

The equivalent expression is equal to (11x-10).

3 0
3 years ago
What are rational numbers
Oksanka [162]
A rational number is any number that can be expressed as the quotient or fraction
6 0
3 years ago
Read 2 more answers
Solve the equation for y.<br> 8x – 9y = 11
pav-90 [236]
8x-9y=11

First you move the 8x because you have to leave the 9y alone

8x-9y=11
-8x        -8x

-9y=11-8x

Now you have to move the -9, so the inverse of multiplying is dividing so you divide -9.

-9y/-9= 11/-9 -8x/-9

since you can't have negative as a denominator it would be:

y= -11/9+8x/9

<span>You have to change the signs</span>
3 0
3 years ago
Evaluate the expression below for x=4 3x+2•|x-8|-12
meriva
3x4= 12+2= 14 (the dot means multiplication) and i dont know further srry :(
7 0
3 years ago
Read 2 more answers
La temperatura a una distancia r del centro de una lámina está dada por T=40 (r2?2r) . La variación instantánea de la temperatur
PilotLPTM [1.2K]

For this, the first thing to do is to assume that the function of temperature with respect to r is written in one of the following ways:

Way 1:

T = 40 (r ^ 2 + 2r)

Way 2:

T = 40 (r ^ 2-2r)

To find the instant variation we must find the derivative of the temperature with respect to the distance r.

We have then:

For function 1:

\frac {dT} {dr} = 40 \frac {d ((r ^ 2 + 2r))} {dr}\\

\frac {dT} {dr} = 40 (2r + 2)

Rewriting

\frac {dT} {dr} = 80r + 80

For function 2:

\frac {dT} {dr} = 40 \frac {d ((r ^ 2-2r))} {dr}

\frac {dT} {dr} = 40 (2r-2)

Rewriting

\frac {dT} {dr} = 80r-80

Answer:

The instantaneous variation of the temperature with respect to r is given by:

Assuming function 1:

\frac {dT} {dr} = 80r + 80

Assuming Function 2:

\frac {dT} {dr} = 80r-80

6 0
3 years ago
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