Please help me on this thank u
1 answer:
If h=0 represents the base of the model, then ...
The bridge touches the base of the model at 2 feet and 6 feet from the leftmost edge of the model.
_____
When in doubt, use your calculator to graph it.
Here, the solution is not so hard. We're looking for h(x) = 0.
Multiply by -2
(x -4)² -4 = 0
(x -4) = ±√4
x = 4 ±2 = {2, 6}
The bridge touches the base of the model at 2 feet and 6 feet from the leftmost edge of the model.
_____
When in doubt, use your calculator to graph it.
Here, the solution is not so hard. We're looking for h(x) = 0.
Multiply by -2
(x -4)² -4 = 0
(x -4) = ±√4
x = 4 ±2 = {2, 6}
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Answer:
602.88 cu ft.
Step-by-step explanation:
V = Bh where B is the area of the base, which is a circle in your problem.
Since the diameter is 8, the radius is 4.
So, B =
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60% of that volume is .60(1004.8) = 602.88 cu ft.
Answer:
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Step-by-step explanation:
Answer:
- The width = x = 14
- The length = x+5 = 14+5 = 19
Step-by-step explanation:
Let l = length, w = width, A = area = l×w , and P = perimeter = 2(l+w)
Let 'x' be the width
As the length 'l' of a rectangle is 5 inches more than its width.
so the length will be = x+5
As the Area of the rectangle is equal to 2 inches more than 4 times the perimeter.
A = 4P + 2
so the equation becomes
l × w = 4×2(l+w)+2
substituting w=x, l = x+5,
(x+5)x = 8(x+5+x)+2
x²+5x = 8(5+2x)+2
x²+5x = 40+16x+2
x²+5x = 16x+42
x²+5x-16x-42 =0
x²-11x-42=0
solving
similarly solving
so
x = 14, or x = -3
As the width 'x' can not be negative.
so x = 14
Thus,
- The width = x = 14
- The length = x+5 = 14+5 = 19