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2 years ago

Question 1

Mathematics

1 answer:

vivado [14]2 years ago

4 0

Answer:

33, 792

Step-by-step explanation:

first convert the 8 miles to feet because our answers are in feet.

1 mile= 5280 feet

therefore 8 miles= 5280×8

= 42240

Dale and son covered 4/5 of the 42240 feet

= 4/5×42240

= 33,782 feet

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The time, T (seconds) it takes for a pot of water to boil is inversely proportional to the cooker setting, H, applied to the pot

kherson [118]

Answer:

200

Step-by-step explanation:

T = x * (1/H)

x = T*H

x = 2800

so for H = 14

T = 2800 * (1/14) = 200

7 0

3 years ago

Consider the following system of equations:

Delicious77 [7]

Answer:

The system has infinitely solutions

Step-by-step explanation:

we have

$-\frac{1}{3}x^{2}=-\frac{5}{6}+\frac{1}{3}y^{2}$

$\frac{1}{3}x^{2}+\frac{1}{3}y^{2}=\frac{5}{6}$

Multiply by 3 both sides

$x^{2}+y^{2}=\frac{5}{2}$ ----> equation A

The equation A is a circle centered at origin with radius $r=\sqrt{5/2}\ units$

and

$5y^{2} =\frac{25}{2}-5x^{2}$

$5x^{2}+5y^{2} =\frac{25}{2}$

Divide by 5 both sides

$x^{2}+y^{2} =\frac{5}{2}$ ----> equation B

The equation B is a circle centered at origin with radius $r=\sqrt{5/2}\ units$

Equation A and Equation B are the same

Therefore

The system has infinitely solutions

7 0

3 years ago

Read 2 more answers

A square and a rectangle have equal areas. If the dimensions of

Katena32 [7]

Answer:

L = 3√5

Step-by-step explanation:

A square and a rectangle have equal areas.

Area of a square = Area of a rectangle

L² = H * W

If the dimensions of the rectangle are 15 units by 3 units,

L² = 15 * 3

L² = 45

Determine the length of the side of the square.

L = √45

L = 3√5

6 0

3 years ago

Read 2 more answers

Each square on a chessboard. 2.7 inches on each side. What area of one square on chessboard. HURRY I NEED THIS TMR

kramer

2.7 * 2.7 = 7.29

Hope this helps

5 0

3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago