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vlada-n [284]
3 years ago
15

Part I: Describe the center and radius of the circle.

Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

Center (2,4) , radius=3, h=2 v=4 & r=3

Step-by-step explanation:

Ok so in order to find the center of the circle, use the graph (like you can see that the x is 2,if you count down from 5 to the left. the y is 4,because it's below 5 in the y pole).So the center is (2,4)

Now, in order to find the length of the radius, you need to do the following:

Take the center point (2,4) and the point where the circle ends (2,1) . Because radius is a straight, you can substract the y values of the two points : 4-1=3

As you can see in the equation, the h symbolizes the x of the center point and the v symbolizes the y.The r is the radius that we already found(3)

So it's shouldn't be a problem now to find the equation of the circle,simply replace the values with their numbers:

(x-2)^2 + (y-4)^2 = 9

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A circle fits inside a semicircle of diameter 24mm
patriot [66]

Answer:

The shaded are is 113\ mm^{2}

Step-by-step explanation:

we know that

The shaded area is equal to the area of the semicircle minus the area of the circle inside the semicircle

step 1

Find the area of semicircle

The area of semicircle is equal to

A=\frac{1}{2}\pi r^{2}

where

r=24/2=12\ mm ----> the radius is half the diameter

substitute

A=\frac{1}{2}\pi(12)^{2}=72\pi\ mm^{2}

step 2

Find the area of the circle inside the semicircle

The area of circle is equal to

A=\pi r^{2}

where

r=12/2=6\ mm ---> the radius of circle inside is half the radius of semicircle

substitute

A=\pi(6)^{2}=36\pi\ mm^{2}

step 3

Find the shaded area

72\pi\ mm^{2}-36\pi\ mm^{2}=36\pi\ mm^{2}

assume

\pi=3.14

36(3.14)=113.04\ mm^{2}

3 significant figures is

113\ mm^{2}

6 0
3 years ago
Graph the polygon and its image after a dilation centered at C(1,1)
Grace [21]

Now we proceed to present the graphs of the polygon and its image with the help of a graphing tool. The <em>original</em> polygon is highlighted in <em>red</em> and the image is highlighted in <em>blue</em>.

DIlations are defined by the follwing operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)] (1)

Where:

  • O(x,y) - Center of dilation.
  • k - Dilation factor.
  • P(x,y) - Original point of the polygon.
  • P'(x,y) - Dilated point of the polygon.

If we know that O(x,y) = (1,1), k = 0.5, J(x,y) = (3,1), K(x,y) = (5, -3), L(x,y) = (5,5) and M(x,y) = (3,7), then the coordinates of the new polygon are:

J'(x,y) = (1,1) + 0.5\cdot [(3,1)-(1,1)]

J'(x,y) = (1,1)+0.5\cdot (2,0)

J'(x,y) = (1,1) +(1,0)

J'(x,y) = (2,1)

K'(x,y) = (1,1) + 0.5\cdot [(5,-3)-(1,1)]

K'(x,y) = (1,1) +0.5\cdot (4,-4)

K'(x,y) = (1,1) +(2,-2)

K'(x,y) = (3,-1)

L'(x,y) = (1,1) + 0.5\cdot [(5,5)-(1,1)]

L'(x,y) = (1,1) + 0.5\cdot (4,4)

L'(x,y) = (1,1) + (2,2)

L'(x,y) = (3,3)

M'(x,y) = (1,1) + 0.5\cdot [(3,7)-(1,1)]

M'(x,y) = (1,1) +0.5\cdot (2,6)

M'(x,y) = (1,1) +(1,3)

M'(x,y) = (2,4)

Now we proceed to present the graphs of the polygon and its image with the help of a graphing tool. The <em>original</em> polygon is highlighted in <em>red</em> and the image is highlighted in <em>blue</em>.

We kindly invite to check this question on dilations: brainly.com/question/13176891

6 0
3 years ago
A group of eight grade 11 and five grade 12 students wish to be on the senior prom committee. The committee will consist of thre
BaLLatris [955]
5/13*4/12*3/11=5/143 I believe
7 0
3 years ago
The graph of function f(x) = √|x − 5| − 2
Bingel [31]

Answer:

It will look like half of a parabola, rotated 90 degrees, originating at (5, -2), and reflected horizontally.

7 0
3 years ago
Math help please!! Thanks in advance.
Marrrta [24]

The third table is the answer.

x=-5 => y=-5-6=-11

x=-8 => y=--8-6=-14

y=-7 => y=-7-6=-13

3 0
2 years ago
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