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3 years ago

1. If we vertically reflect the Figure A,

1 answer:

3 0

When reflecting points you need to recognize which quadrant the original points are. (4,3) is in the (+,+) quadrant so when reflected over the y axis is (-4,3) and (4,0) is still (4,0)

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If 3 = 1/2gt^2, make t the subject of the formula

Montano1993 [528]

Answer:

t = √1.5/g

Step-by-step explanation:

1/2gt^2 = 3

Divide both sides by 1/2

gt^2 = 1.5

Divide both sides by g

t^2 = 1.5/g

Square root both sides

t = √1.5/g

5 0

2 years ago

How much smaller is x−3 than x+4?

Lilit [14]

Answer: bsf google

Step-by-step explanation: go to google look it up and find the answer

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3 years ago

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cConsider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,

quester [9]

Expected value = -1(1/6) + 2(1/6) + 3(1/6) - 4(1/6) + 5(1/6) - 6(1/6) = -1/6 + 2/6 + 3/6 - 4/6 + 5/6 - 6/6 = -1/6 = -0.167

4 0

3 years ago

Read 2 more answers

Solve the equation 5x-2x^2+1

Pani-rosa [81]

Answer:

Step-by-step explanation:

If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:

5x-2x^2+1 = 0

This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:

-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.

Use the quadratic formula to solve for x:

First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33

Because the discriminant is positive, the roots of this quadratic are real and unequal.

-b ± √(discriminant)

Applying the quadratic formula x = --------------------------------

we get:

-5 ± √33 -5 + √33

x = ----------------- = --------------------- and

2(-2) -4

-5 - √33

---------------

-4

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2 years ago

What is the mass (in grams) of 8.11×1026 CO2 molecules?

Kobotan [32]

Answer:

It is 59,275.74 grams

Step-by-step explanation:

• Molecular mass of carbon dioxide

$= (12 \times 1) + (16 \times 2) \\ = 12 + 32 \\ = 44 \: g$

[ molar masses: C = 12 g, O = 16 g ]

• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.

But 1 mole is equivalent to its molar mass in terms of weight, therefore;

${ \sf{6.02 \times {10}^{23} \: molecules = 44 \: g }}\\ { \sf{8.11 \times {10}^{26} \: molecules =( \frac{8.11 \times {10}^{26} }{6.02 \times {10}^{23} } \times 44) \: g}} \\ \\ = { \boxed{ \boxed{ \bf{59275.7 \: \: g}}}}$

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2 years ago