Answer:
A
Step-by-step explanation:
Nonlinear would be any function where both values are not changing by some fixed amount. In B, f(x) increases by 1 for every time x increases by 1 so that's linear. For C, f(x) increases by 2 for every time x increases by 1, so that's linear. For D, f(x) increases by 3 for every time x increases by 1 so that's also linear. For A, f(x) does not always change by the same amount, so it's nonlinear.
Length: 2w + 59
width: w
diagonal: (2w + 59) + 2 = 2w + 61
Length² + width² = diagonal²
(2w + 59)² + (w)² = (2w + 61)²
(4w² + 118w + 3481) + w² = 4w² + 122w + 3721
5w² + 118w + 3481 = 4w² + 122w + 3721
w² + 118w + 3481 = 122w + 3721
w² - 4w + 3481 = 3721
w² - 4w - 240 = 0
a = 1, b = -4, c = -240
w = ![[-(b) +/- \sqrt{(b)^{2} - 4(a)(c) }]/2(a)](https://tex.z-dn.net/?f=%5B-%28b%29%20%2B%2F-%20%5Csqrt%7B%28b%29%5E%7B2%7D%20%20-%204%28a%29%28c%29%20%7D%5D%2F2%28a%29)
= ![[-(-4) +/- \sqrt{(-4)^{2} - 4(1)(-240) }]/2(1)](https://tex.z-dn.net/?f=%5B-%28-4%29%20%2B%2F-%20%5Csqrt%7B%28-4%29%5E%7B2%7D%20%20-%204%281%29%28-240%29%20%7D%5D%2F2%281%29)
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since width cannot be negative, disregard 1 - 2√61
w = 1 + 2√61 ≈ 16.62
Length: 2w + 59 = 2(1 + 2√61) + 59 = 2 + 4√61 + 59 = 61 + 4√61 ≈ 92.24
Answer: width = 16.62 in, length = 92.24 in
Answer:
(8, 0 )
Step-by-step explanation:
under a reflection in the line y = - x
a point (x, y ) → (- y, - x ) , then
(0, - 8 ) → (8, 0 )
For number 3 it is 56 pints! i’ll do the other ones in a second
3 squares = 4 circles, so (number of squares)/(number of circles) = 3/4.
3/4 = 12/16
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4 squares = 2 circles, so (number of squares)/(number of circles) = 4/2.
4/2 = 2/1
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2 squares = 5 circles, so (number of squares)/(number of circles) = 2/5.
2/5 = 4/10