Answer:
The area of the window will be equal to 195 sq. inches.
Step-by-step explanation:
On a boat, a cabin's window is in the shape of an isosceles trapezoid.
The longer side parallel side is at the bottom.
The top side of the trapezoid is 10 inches and the height is 15 inches and the base of the triangle formed from the height on the right is labeled 3 inches.
So, the bottom parallel side has length of (10 + 3 + 3) = 16 inches.
Therefore, the area of the window will be equal to 
sq. inches. (Answer)
Suppose the angles measures are 2x, 5x, and 9x
the three angles make a total of 180: 2x+5x+9x=180
16x=180
x=11.25
so the three angles are 22.5, 56.25, and 101.25 respectively
a little odd, but those should be the measurements.
$90 - $30 = $60
$60 - $10 = $50
50 divided by 3* =
16.6666667
3*: from the 3 pencils that Jason also wants.
9514 1404 393
Answer:
77
Step-by-step explanation:
We can use a number of ratio units to represent b that is the LCM of 8 and 6. That value is 24. Then multiplying the first ratio by 3 and the second by 4, we have ...
a:b = 9:24 and b:c = 24:44
Then the ratios of all are ...
a : b : c = 9 : 24 : 44
and the sum is 9+24+44 = 77.
Answer:
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
Let
x------> size of the event space
y-----> size of the sample space
so
step 1
Find the probability that a point chosen randomly inside the rectangle is in the circle
<em>Find the area of the rectangle</em>
<em>Find the area of the circle</em>
In this problem we have
substitute
step 2
Find the probability that a point chosen randomly inside the rectangle is in the regular hexagon
<em>Find the area of the regular hexagon</em>
![A=6[\frac{1}{2} (1.8)^{2}sin(60)]=8.42\ in^{2}](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%20%281.8%29%5E%7B2%7Dsin%2860%29%5D%3D8.42%5C%20in%5E%7B2%7D)
In this problem we have
substitute
step 3
Find the probability that a point chosen randomly inside the rectangle is either in the circle or in the regular hexagon
Is the sum of the two probabilities
Round to the nearest hundredth
