Answer:
-1
Step-by-step explanation:
Plug in given values
-4x + 5y + 6z
-4(-2) + 5(3) + 6(-4)
8 + 15 -24
23-24
-1
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
answer becit uses b
Step-by-step explanation:
but yass queen but annyway
Answer:
The x-intercept represents when the water level of the Eastview pond. This shows that the Eastview pond's water level reached 0 at 52 (days/years/hours/minutes... etc).
Answer:
3.5 m
Step-by-step explanation:
Use sine.
1. Set up the equation using sin = opposite / hypotenuse
sin 59 = 3/x
2. Solve
x = 3.5
