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3 years ago

If element x has 44 protons how many electrons does it have?

1 answer:

5 0

The correct answer is '44'.

In fact, the atom of an element has an equal number of protons and electrons: therefore, if element X has 44 protons, it should have 44 electrons as well.

For curiosity: the chemical element with 44 protons and 33 electrons is Ruthenium.

You might be interested in

The magnitude of electrical force between a pair of charged particles is ____ as much when the particles are moved half as far a

Gnesinka [82]

The magnitude of the electrical force between a pair of charged particles is 4 Times as much when the particles are moved half as far apart.

This can be easily understood by Columb's law,

$F_{new} = \frac{kQ_{1}Q_{2}}{r^{2}}$

which state's that the amount of electrical force experienced by two charged particles is inversely proportional to the square of the distance between them.

∴ $\frac{F_{new} }{F_{old} } = \frac{Distance_{new}^{2} }{Distance_{old}^{2} }$

Now, we know the new distance is half the original distance,

$F_{new} = \frac{kQ_{1}Q_{2}}{\frac{r}{2}^{2} } \\F_{new} = 4\frac{kQ_{1}Q_{2}}{r^{2}}$

$F_{new} = 4F_{old}$

The electrical force of attraction or electrostatic force of attraction between two charged particles refers to the amount of attractive or repulsive force that exists between the two charges. This can be calculated by Columb's Law.

A charged particle in physics is a particle that has an electric charge. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. The same charge is thought to be shared by an electron, a proton, or another primary particle.

Learn more about electrical force here

brainly.com/question/2526815

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8 0

1 year ago

The drawing on the right shows a man (mass = 70kg) and the child (mass = 35 kg) push each other apart. The man moves away with a

Pepsi [2]

Answer:

<h2>Hope it would help you.</h2>

3 0

3 years ago

Read 2 more answers

26. ____________ is a chemical reaction between an acid and a base that produces a salt and water

Anuta_ua [19.1K]

26 neutralization reaction;
27 positive ions;
28 titrations;
29 bases;
30 buffers

3 0

3 years ago

2 masses of 4kg and 2.5kg have a separation of r =1.5m. Calculate the force of gravitational attraction between them (take g as

Evgesh-ka [11]

Answer:

F = 29.64 × 10-¹¹N

Explanation:

From newton's law of gravitation which states that every object in the universe will attract each other with a force which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

That is, F = (Gm1m2)/ r²

From the question m1=4kg, m2 = 2.5kg, r= 1.5m,G = 6.67×10-¹¹

F=( 6.67×10-¹¹ × 4 × 2.5) / 1.5²

F = (66.7×10-¹¹) / 2.25

F = 66.7/2.25 × 10-¹¹ N

F = 29.64 × 10-¹¹N

I hope this was helpful, please mark as brainliest

5 0

3 years ago

where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distan

zavuch27 [327]

      Force = G · m₁ · m₂   /   r²

In all SI units . . .

[ newton ] = [ G ] · [kg] · [kg] / [meter²]

But 'newton' is kg-m / s²
So the formula says

      [ kg-m / s² ] = [ G ] · [kg] · [kg] / [meter²]

Divide each side
by kg² : kg-m / s²-kg² = [ G ] / meter²

Multiply each side
by meter² : kg-m-m² / s²-kg² = G

Cancel 'kg' from
top and bottom: m-m² / s²-kg = G

Clean it up: <span> [ G ] = m³ / kg - s² <==

Check:
Look up "Gravitational constant" on-line:
</span>Gravitational constant = 6.67408 × 10-11 m³ kg⁻¹ s⁻² <== yay !<span />

8 0

3 years ago