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seropon [69]
3 years ago
12

Define a variable and write an expression for the phrase.

Mathematics
2 answers:
allsm [11]3 years ago
8 0

Answer:

6-n

Step-by-step explanation:

it is subtracting a number from 6

I hope this helps!

dalvyx [7]3 years ago
7 0

6-n because n is equivalent to a number

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I need help on this one
notka56 [123]

Answer:

(3,5)

1/3

Step-by-step explanation:

The equation is already in point-slope form. Therefore, both the point and slope can easily be found in the equation. Point slope form looks like y-y_{1}=m\left(x-x_{1}\right). In this the point is (x_{1},y_{1}) and the slope is m. So, the x value is 3 and the y value is 5, making the coordinate (3,5). Finally, the slope is 1/3.

5 0
2 years ago
Read 2 more answers
Factor the polynomial: – 43 – 4x2 - 5x
Sedaia [141]

Answer:

Step-by-step explanation:

i think you messed up the options, but assuming the function is this:

-x^3-4x^2-5x

then the correct factorized form is:

-x(x^2+4x+5)

4 0
3 years ago
Please help with the following maths question
zavuch27 [327]

Answer:

120 degrees

Step-by-step explanation:

Regular hexagon means all the sides are equal

(6-2)(180)=The sum of interior angles of hexagon

=>720 degree

Therefore each angle=720/number of sides

=720/6=120 degree

So let the marked angle in figure be 'x'

And the adjacent equal angles to x, y

So y+y+x=360 [Angle around point=360]

2y+x=360 [but y=120 degree proved]

240+x=360

x=120

6 0
3 years ago
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The tape diagram represents an equation.<br> Write an equation to represent the image.
den301095 [7]

Answer:

please join mine meet and we can talk

Step-by-step explanation:

4 0
3 years ago
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In how many ways can you arrange 6 digits to make a 3-digit number without repeating a digit?
White raven [17]
The number of ways n different objects can be arranged, taking r objects at a time, without repeating any object is given by:

^nP_r= \frac{n!}{(n-r)!}

Given 6 different digits, the number of ways to arrange 6 different digits to make a 3 digit number without reapeating a digit is given by:

^6P_3= \frac{6!}{(6-3)!} \\  \\ = \frac{6!}{3!} = \frac{6\times5\times4\times3!}{3!}  \\  \\ =6\times5\times4=120

Therefore, the number of <span>ways 6 digits can be arranged to make a 3-digit number without repeating a digit</span> is 120 ways.
5 0
4 years ago
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