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3 years ago

Someone one help me it involves problem solving with linear models i believe it is c

Mathematics

1 answer:

yaroslaw [1]3 years ago

6 0

Y-intercept in this case means the average cost of a ticket in year 2005

then it increased

So it is A

If you still need help, just let me know!

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Solve the given equation. State the number and type of roots. x^2+2x-8=0

Zinaida [17]

I hope this helps you

3 0

3 years ago

How do you simplify this expression?

mash [69]

First we will find all factors under the square root: 147 has the square factor of 49.Let's check this width √49*3=√147. As you can see the radicals are not in their simplest form.Now extract and take out the square root √49 * √3. Root of √49=7 which results into 7√3All radicals are now simplified. The radicand no longer has any square factors.

the answer is 7√3

hopes thats helps

3 0

4 years ago

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Name a cube using the words parallel and perpendicular

babymother [125]

Box and it has parallel lines and it has a perpendicular degrees of 90%

5 0

3 years ago

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A total of 8 representatives need to be chosen from a group of 40 students, of which 24 are female and 16 are male. In how many

Diano4ka-milaya [45]

Answer:

Probability = 0.0147

Step-by-step explanation:

To find this, we need to know the number of ways the representatives can be picked overall, and then the number of ways 3 females and 3 males can be the representatives. The fraction of the two will be the probability.

The total number of ways the representatives can be picked is the combination of a pool of 40 students and choosing 8 is; C(40,8) = 40!/((8!)(40 - 12)!)

= 76904685

We have gotten the number of ways the representatives can be picked.

Now let's find how many ways can the jury consist of 3 females and 3 males

For the males, there are 16 in the pool and we're picking 3:

Thus, C(16,3) = 16!/((3!)(16 - 3)!) = 560

For the females, there are 24 in the pool and we're picking 3:

Thus, C(24,3) = 24!/((3!)(24 - 3)!) = 2024

Thus, number of men and women choices = 2024 x 560 = 1133440

So; probability = 1133440/76904685 = 0.0147

3 0

3 years ago

How many 3-digit even numbers are that begin with either 5 or 6?

mojhsa [17]

Answer: 100 3 digit even number that begin with either 5 or 6

Explanation:
Case 1:
A 3 digit that begin with 5 should be 500-599 so there are 100 numbers
But we are only finding even number
So 100/2 = 50 3-digit even number that begin with 5.

Case 2:
A 3 digit that begin 6 should have
600-699 and there are also 100 number including even and odd in total. Since we are only finding even number we get:
100/2 = 50 3-digit even number that begin with 6.

Plus both case together we get 50 3-digit even number that begin with 5 + 50 3-digit even number that begin with 6= 50 + 50 = 100

8 0

4 years ago

Read 2 more answers