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maria [59]
3 years ago
14

How many 3-digit even numbers are that begin with either 5 or 6?

Mathematics
2 answers:
mojhsa [17]3 years ago
8 0
Answer: 100 3 digit even number that begin with either 5 or 6

Explanation:
Case 1:
A 3 digit that begin with 5 should be 500-599 so there are 100 numbers
But we are only finding even number
So 100/2 = 50 3-digit even number that begin with 5.

Case 2:
A 3 digit that begin 6 should have
600-699 and there are also 100 number including even and odd in total. Since we are only finding even number we get:
100/2 = 50 3-digit even number that begin with 6.

Plus both case together we get 50 3-digit even number that begin with 5 + 50 3-digit even number that begin with 6= 50 + 50 = 100
Alex17521 [72]3 years ago
5 0

Answer:

100

Step-by-step explanation:

500 to 599 =100 100/2=50

600 to 699=100 100/2=50

50+50=100

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Andru [333]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Answer:

≥

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7 0
3 years ago
Please help please please
alexgriva [62]
Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}

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Thats 6 of the 10 numbers 

6/10
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8 0
4 years ago
What is 6/5 divided by 4/10
Sidana [21]
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6 0
3 years ago
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Answer:  

3/4

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