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3 years ago

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mr. Nolan's code for ATM card is a four digit number. the digits of the code are prime factors of 84 listed from least to greate

st. what is the code for mr. Nolan's ATM card

1 answer:

Artemon [7]3 years ago

8 0

Answer:

84/2= 42, 42/7= 6, 6/3= 2

84 = 2 x 2 x 3 x 7

ATM card = 2237

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Answer:

Step-by-step explanation:

Lets calculate the fence first!

15*12=180

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Turn this into a linear equation

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Divide by 250 on both sides:

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So, Mario needs 0.72 Gal of paint to paint the fence!

<em>Hope i helped, Brainliest would be appreciated!</em>

<em>Have a nice day!</em>

<em> -Aadi x</em>

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Do you want The answer?

5 0

3 years ago

How do you understand it

maks197457 [2]

431 ≈ 400
115 ≈ 100
400 - 100 = 300

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4 years ago

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The sum of 30 times (1/3)^(n-1) from 1 to infinity

sergeinik [125]

Let

$S_n=\displaystyle1+\frac13+\frac1{3^2}+\cdots+\frac1{3^n}$

Then

$\dfrac13S_n=\displaystyle\frac13+\frac1{3^2}+\frac1{3^3}+\cdots+\frac1{3^{n+1}}$

and

$S_n-\dfrac13S_n=\dfrac23S_n=1-\dfrac1{3^{n+1}}\implies S_n=\dfrac32-\dfrac1{2\cdot3^n}$

and as $n\to\infty$ , we end up with

$\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{i=1}^{n+1}\frac1{3^{i-1}}=\lim_{n\to\infty}\left(\frac32-\frac1{2\cdot3^n}\right)=\frac32$

So we have

$\displaystyle\sum_{n=1}^\infty30\left(\frac13\right)^{n-1}=30\cdot\frac32=45$

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3 years ago