Answer:
a. Maurice walked farther.
b. 0.62 m
Step-by-step explanation:
Maurice
4.1 × 1.8 = 7.38 miles
Junnie
2.5 × 3.2 = 8 miles
This shows that Junnie walked more than Maurice.
8 - 7.38 = 0.62
Junnie walked 0.62 m more than Maurice
The expression to find the number of notebooks James bought would be written as:
Number of notebooks = total spent / cost per item
Number of notebooks = (2y^2 + 6) / <span>(y^2 − 1)
</span><span>If y = 3, then the number of notebooks bought would be:
</span>Number of notebooks = (2y^2 + 6) / (y^2 − 1)
Number of notebooks = (2(3)^2 + 6) / (3^2 − 1)
Number of notebooks = 3 pieces<span>
</span><span>
</span>
Avg. speed Joanna runs: 7.5km/h
how much she runs everyday: 15km
15km/7.5= 2 hours of running time everyday
She leaves at 8:30, comes back at ?
8:30+ 2:00= 10:30
Joanna arrives back at 10:30a.m.
Answer:
Explicit tn = 52 + (n - 1)*(-12)
Recursive = tn = t(n - 1) - 12
Step-by-step explanation:
The difference between term n and term n - 1 is can be found by taking the difference between and 2 consecutive terms.
t3 = 28
t2 = 40
d = t3 - t2
d = 28 - 40
d = - 12
Explicit
tn = a1 + (n - 1)*d
a1 = 52
d = - 12
tn = 52 + (n - 1)*(-12)
<em><u>Example</u></em>
Find t5
t5 = 52 + (5 - 1)*(-12)
t5 = 52 + 4 * - 12
t5 = 52 - 48
t5 = 4
Recursive
tn = t(n - 1) - 12
<em><u>Example</u></em>
t5 = t4 - 12
t5 = 16 - 12
t5 = 4 just as it did before.
1) This is not an arithmetic sequence because it has n².
2) To find 5 first terms of this sequence, you can simply substitute n with 1,2,3,4, and 5, and calculate values of a(1),a(2), a(3), a(4) and a(5).
a(n) = 3n²- 1
n=1 a=3*1² - 1 = 3-1=2
n=2 a=3*2² - 1 = 11
n=3 a=3*3² - 1 =26
n=4 a=3*4² - 1 = 47
n=5 a=3*5² -1 = 74
2,11,26,47,74
Answer C. 2,11,26,47,74.
