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LUCKY_DIMON [66]
3 years ago
11

What is the period, in seconds, of a simple pendulum of length 3 meters? Use the gravitational constant g = 9.8 m/s2 and round y

our answer to two decimal places.
Mathematics
2 answers:
Nadya [2.5K]3 years ago
8 0

Answer:

the period, in seconds = 3.47 s

Step-by-step explanation:

Given:

length of pendulum, l= 3 m

gravitational constant, g=9.8 m/s^2

Period of pendulum, T= ?

Applying formula for period of pendulum:

T=2π√(l/g)

Putting values we get:

T=2π√(3/9.8)

T=3.47 s!

Licemer1 [7]3 years ago
8 0

Answer:

The answer is 3.47638 (AP3X)

Rounded it is 3.48

Step-by-step explanation:

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