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lana66690 [7]
4 years ago
10

What is the 4th term

Mathematics
1 answer:
Dimas [21]4 years ago
8 0
4th term is the mathematical calculation of the number given in its fourth calculation
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4 years ago
What is the best esimate for the following quotient <br>891.3÷28
arsen [322]

32

31.832142857 is what you got, look at your tenths digit. if it's greater or equal to 5, it will always round to the higher number. if its less than or equal to 4, it will be the lower number.

for example, 10.4 will be 10, as it is lower than 5

or 10.6 will be 11 cause it is higher than 5

8 0
3 years ago
PLEASE HELP                                                                                                                    
sweet [91]
To model and solve our situation we are going to use the equation: s= \frac{d}{t}
where
s is speed
d is distance 
t is time 

1. We know that the distance between the cities is 2400 miles, so d=2400. We also know that the speed of the plane is 450 mi/h. Since we don't know the speed of the air, S_{a}=?. We don't know how much the westward trip takes, so t_{w}=?, and we also don't know how much the eastward trip takes, so t_{e}=?.

Going westward. Here the plane is flying against the air, so we need to subtract the speed of the air from the speed of the plane:
450-S_{a}= \frac{2400}{t_{w} }
Going eastward. Here the plane is flying with the the air, so we need to add the speed of the air to the speed of the plane:
450+S_{a}= \frac{2400}{t_{e} }

2. We know for our problem that the round trip takes 11 hours; so the total time of the trip is 11, t_{t}=11. Notice that we also know that the total time of the trip equals time of the tip going westward plus time of the trip going eastward, so t_{t}=t_{w}+t_{e}. Since we know that the total trip takes 11 hours, we can replace that value in our total time equation and solve for t_{w}:
11=t_{w}+t_{e}
t_{w}=11-t_{e}

Now we can replace t_{w} in our going westward equation to model our round trip with a system of equations:
450-S_{a}= \frac{2400}{t_{w}}
450-S_{a}= \frac{2400}{11-t_{e} } equation (1)
450+S_{a}= \frac{2400}{t_{e}} equation (2)

3. To solve our system of equations, we are going to solve for t_{e} in equations (1) (2):

From equation (1)
450-S_{a}= \frac{2400}{11-t_{e} }
11-t_{e}= \frac{2400}{450-S_{a} }
-t_{e}= \frac{2400}{450-S_{a} } -11
t_{e}=11- \frac{2400}{450-S_{a} }
t_{e}= \frac{4950-11S_{a} -2400}{450-S_{a} }
t_{e}= \frac{2550-11S_{a} }{450-S_{a} } equation (3)

From equation (2):
450+S_{a}= \frac{2400}{t_{e} }
t_{e}= \frac{2400}{450+S_{a} } equation (4)

Replacing (4) in (3)
\frac{2400}{450+S_{a}} = \frac{2550-11S_{a}}{450-S_{a} }
Now, we can solve for S_{a} to find the speed of the wind:
2400(450-S_{a})=(450+S_{a})(2550-11S_{a})
1080000-2400S_{a}=1147500-4950S_{a}+2550S_{a}-11(S_{a})^{2}
11(S_{a})^{2}-67500=0
11(S_{a})^{2}=67500
(S_{a})^{2}= \frac{67500}{11}
S_{a}=+/-  \sqrt{ \frac{67500}{11} }
Since speed cannot be negative, the solution of our equation is:
S_{a}= \sqrt{ \frac{67500}{11} }
S_{a}=78.33

We can conclude that the speed of the wind is 78 mph.

3 0
4 years ago
!!!!!!!!15 POINTS FOR ANSWERING THIS CORRECTLY!!!!!!!!
Georgia [21]
<span> graph of y = [x] for -2 ≤ x ≤ 2 </span>

4 0
3 years ago
Together, teammates Pedro and Ricky got 2678 base hits last season. Pedro had 282 more hits than Ricky. How many hits did each p
irga5000 [103]

Answer:

pedro- 1621

ricky- 1057

Step-by-step explanation:

3 0
3 years ago
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