We can solve this system of equations using substitution.
2y + 2x = 8
Solve for x.
2x = -2y + 8
Divide all terms by 2.
x = -y + 4
Take the equation x = -y + 4 and substitute it into the second system of equation.
2y - 4x = 2
2y - 4(-y + 4) = 2
Simplify by distributing.
2y + 4y - 16 = 2
Combine like terms.
6y - 16 = 2
6y = 18
y = 3
Now that you know the numerical value of y, substitute y with 3 in both equations to find x.
1) 2y + 2x = 8
2(3) + 2x = 8
6 + 2x = 8
2x = 2
x = 1
2) 2y - 4x = 2
2(3) - 4x = 2
6 - 4x = 2
-4x = -4
x = 1
The value of x is 1, and the value of y is 3.
Solution: B) (1, 3)
The limits to the given function are as follows:
1. ∞
2. -∞
3. ∞
4. 1
5. -∞
<h3>What is a limit?</h3>
A limit is given by the <u>value of function f(x) as x tends to a value</u>.
For this problem, at x = 0, we have that to the left the function goes to positive infinity, while to the right it goes to negative infinity, hence:
1. lim f(x) = ∞
x->0-
2. lim f(x) = -∞
x->0+
At x = 2, the function goes to infinity to the left and to the right, hence:
3. lim f(x) = ∞
x->2
To the left of the graph, the function goes to negative infinity, while to the right it goes to 1, hence:
4. lim f(x) = 1
x-> ∞
5. lim f(x) = -∞
x-> -∞
More can be learned about limits of functions at brainly.com/question/26270080
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The answer of this question is 13/24
Answer:
.
Step-by-step explanation:
Answer:
6 units
Step-by-step explanation:
The formula for the area of a rectangle = Length × Width
A rectangle’s width is one-fourth of its length.
W = 1/4 × L
W = L/4
Cross Multiply
L = 4W
A = 9 square units
Hence
9 = L × W
We substitute 4W for L
9 = 4W × W
9 = 4W²
We square root both side
√9 = √4W²
3 = 2W
W = 3/2
W = 1 1/2 unit or 1.5 units
Solving for L = Length
9 = L × W
9 = L × 1.5
L = 9/1.5
L = 6 units
Therefore, the Length of the rectangle = 6 units
