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iragen [17]
3 years ago
14

Early one February morning you go outside to build a snow man. You make a 3.2kg snowball and lift it to a height of 1.2m, then c

arry it 25m on level ground with a force of 1.0N to your snowman and then lift it up the rest of the way to set as the head of a 2.3m snowman. How much work do you do on the snowball as you transport it and position it on your masterpiece?
Physics
2 answers:
Verdich [7]3 years ago
4 0

First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.

Therefore mass× gravitational pull×height will give us the work done

=3.2kg ×9.8N/kg×1.2m

=37.632J

then, the work done over the 25m distance if found by the following formula: work done=force×distance

=1.0N×25m

=25J

On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.

therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m

=m×g×h

=3.2kg×9.8N/kg×1.1m

=34.496J

To get the total we add the amount of work done in the various instances.

djverab [1.8K]3 years ago
3 0

Here you go

First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.


Therefore mass× gravitational pull×height will give us the work done


=3.2kg ×9.8N/kg×1.2m


=37.632J


then, the work done over the 25m distance if found by the following formula: work done=force×distance


=1.0N×25m


=25J


On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.


therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m


=m×g×h


=3.2kg×9.8N/kg×1.1m


=34.496J


To get the total we add the amount of work done in the various instances.



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Explanation:

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<em>See attachment</em>

Required

Determine the radius of magnesium atom (R)

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