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ivanzaharov [21]
3 years ago
5

I need help!!!!!!!

Physics
1 answer:
wlad13 [49]3 years ago
4 0
One simple use of the elements of the electromagnetic spectrum that we use during our everyday lives is our daily use of microwave radiation. microwave radiation is absorbed by water molecules which heats up and cooks the food whilst killing bacteria. Another would be ultraviolet radiation which we use daily in things such as light bulbs. The sun also uses this. Lastly, we use radio waves constantly. May it be tv programs, radio, or our cell phones.
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What is the amount of "stuff in an object?
Andrei [34K]
Good question. The amount of 'stuff' in an object is it's mass. 

A fundamental distinction we learn in physics is the difference between mass and weight. If we were in deep space, away from any very large objects of mass (like a planet), we would be 'weightless' e.g. not feel the effects of gravity, but we would not be 'massless'. Our mass doesn't change based upon our proximity to large objects (gravitational attraction), but the sense of weight does.
4 0
3 years ago
Read 2 more answers
A battery can be modeled as a source of emf in series, with both a resistance of 10Ωand an inductive reactance of 5
Fiesta28 [93]

Answer:

Explanation:

For circuit in resonance , inductive and capacitive reactance should be equal. Since in the given circuit ,  these two are not equal, the circuit is not in resonance. It does not depend upon voltage provided.

option b is correct.

With this load, the  fraction of the average power, put out by the source of emf,  delivered to the load can be calculated as follows

Power delivered to resistor will be 2/3 rd of total power delivered by source because resistance has value twice that of reactance of capacitor.  So the correct option is .7

option D ) is correct.

3 0
4 years ago
Please Help! Im dumb.
Rus_ich [418]
The answers false I believe
8 0
4 years ago
Read 2 more answers
A crane raises a 12,000 N marble sculpture at a constant velocity onto a pedestal 1.5 m above the ground outside an art museum.
Simora [160]

For the work, applicate formula:

\boxed{\boxed{\green{\bf{W = F\times d}}}}

According our data:

  • Replacing:

W = 12000 N * 1,5 m

  • Resolving:

W = 18000 J

The work done is <u>18000 Joules.</u>

7 0
3 years ago
If your front lawn is 16.016.0 feet wide and 20.020.0 feet long, and each square foot of lawn accumulates 13501350 new snowflake
asambeis [7]

Answer:

The mass of snow accumulated in the lawn in 1 hour equals 57.024 kilograms

Explanation:

Given

Width of lawn = 16 feet

Length of lawn = 20 feet

Thus total area of lawn equals 16\times 20=320sq.feet\

Now it is given that 1 square foot accumulates 1350 new snowflakes each minute thus number of snowflakes accumulated by 320 square feet in 1 minute equals

320\times 1350=432000

Now it is given that average mass of each snowflake is 2.20mg=2.20\times 10^{-3}g=2.20\times 10^{-6}kg

Hence the mass accumulated per minute equals 432000\times 2.20\times 10^{-6}=0.9504kg

Now since there are 60 minutes in 1 hour thus the mass accumulated in 1 hour equals 0.9504kg\times 60=57.024kg

4 0
3 years ago
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