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dimaraw [331]
3 years ago
6

Point Q is plotted on the coordinate grid. Point P is at (10, −20). Point R is vertically above point Q. It is at the same dista

nce from point Q as point P is from point Q. Which of these shows the coordinates of point R and its distance from point Q?
On a coordinate grid from negative 50 to positive 50 in increments of 10, Point Q is plotted at the ordered pair negative 20, negative 20.

Point R is at (−20, −30), a distance of 10 units from point Q
Point R is at (−20, 10), a distance of 30 units from point Q
Point R is at (−20, −10), a distance of 30 units from point Q
Point R is at (−20, 30), a distance of 10 units from point Q

Mathematics
2 answers:
larisa86 [58]3 years ago
7 0

Answer:

Point R is at (−20, 10), a distance of 30 units from point Q                

Step-by-step explanation:

bixtya [17]3 years ago
3 0

Answer:

Point R is at (−20, 10), a distance of 30 units from point Q

Step-by-step explanation:

Q has coordinates (-20,-20).

P has coordinates (10,-20)

Since point R is vertically above point Q, it will have the same x-coordinate as Q.

Let R have coordinates (-20,y).

It was given that;

|RQ|=|PQ|

\Rightarrow |y--20|=|10--20|

\Rightarrow y+20=10+20

\Rightarrow y=10+20-20

\Rightarrow y=10.

The coordinates of R are (-20,10).

The dstance from Q is 30 units.

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Murljashka [212]

Answer:

Al estudiante le falta caminar \frac{1}{3} de kilómetro.

Step-by-step explanation:

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio. Dos tercios equivale a la fracción \frac{2}{3} .

El estudiante avanza medio kilómetro en bus. Un medio equivale a la fracción \frac{1}{2}, por lo tanto un medio es la mitad de una cantidad.  Para calcular la distancia recorrida en bus se realiza la siguiente multiplicación:

\frac{1}{2} *\frac{2}{3}

Resolviendo:

\frac{1}{2} *\frac{2}{3} =\frac{1*2}{2*3} =\frac{2}{6} =\frac{1}{3}

Entonces, la distancia recorrida en bus es \frac{1}{3} de kilómetro.

Para calcular la distancia recorrida a pie se calcula la diferencia entre la distancia total a recorrer por el estudiante y la distancia recorrida en bus. Esto es:

\frac{2}{3} - \frac{1}{3}

Resolviendo:

\frac{2}{3} - \frac{1}{3}=\frac{2-1}{3} =\frac{1}{3}

<u><em>Al estudiante le falta caminar </em></u>\frac{1}{3}<u><em> de kilómetro.</em></u>

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Step-by-step explanation:

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