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3 years ago

What is the probability of rolling a 4 on a single sided die and then rolling a 6?

Mathematics

1 answer:

Rzqust [24]3 years ago

4 0

Answer:

If it is a six-sided die then it has the probability of 1/6 or .16

Step-by-step explanation:

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What is the solution set for

Mumz [18]

Answer: C. (-3, 9)

Step-by-step explanation:

Given

2|x-3|=12

Divide both sides by 2

2|x-3|/2=12/2

|x-3|=6

Take of absolute value sign (REMEMBER need to take into consideration of two conditions)

x-3=±6

1)x-3=6

x=9

2)x-3=-6

x=-3

**NOTE**: need to check each solution whether or not they are suitable

Hope this helps!! :)

Please let me know if you have any questions

5 0

3 years ago

Marcos delivers newspapers during his summer break. He delivers a different number of papers each day. What percent of the total

soldier1979 [14.2K]

Is there some sort of graph or second part to this?

7 0

3 years ago

Read 2 more answers

Plz help this is from Khan academy ty!!

Trava [24]

Answer:

The answer is A

7 0

2 years ago

The library in Richmond collected $4,170 in overdue fees last year. This year, the library collected $6,672. What is the percent

melamori03 [73]

Answer:

not sure just need points and

Step-by-step explanation:

4 0

2 years ago

Find the minimum sample size needed to estimate the percentage of Democrats who have a sibling. Use a 0.1 margin of error, use a

Brums [2.3K]

Answer:

The minimum sample size is $n =135$

Step-by-step explanation:

From the question we are told that

The confidence interval is $( lower \ limit = \ 0.44,\ \ \ upper \ limit = \ 0.51)$

The margin of error is $E = 0.1$

Generally the sample proportion can be mathematically evaluated as

$\r p = \frac{ upper \ limit + lower \ limit }{2}$

$\r p = \frac{ 0.51 + 0.44}{2}$

$\r p = 0.475$

Given that the confidence level is 98% then the level of significance can be mathematically evaluated as

$\alpha = 100 - 98$

$\alpha = 2\%$

$\alpha =0.02$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

The value is

$Z_{\frac{\alpha }{2} } = 2.33$

Generally the minimum sample size is evaluated as

$n =[ \frac { Z_{\frac{\alpha }{2} }}{E} ]^2 * \r p (1- \r p )$

$n =[ \frac { 2.33}{0.1} ]^2 * 0.475(1- 0.475 )$

$n =135$

6 0

3 years ago