Answer:
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Lets take one element from Group 6A, Let it be oxygen, The electronic configuration of Oxygen is as follow,
O = 8 = 1s², 2s², 2px², 2py¹, 2px¹
There are 6 electrons in the valence shell of elements present in Group 6A. The unpaired electrons in 2px and 2py are involved in forming covalent bond, while the pair of electrons in 2s and 2px are unshared and act as lone pair of electrons.
Result:
There are TWO unpaired electrons present in the ground state of Group 6A elements.
The pressure inside the flask on heating it is given as 1.21 atm.
<u>Explanation:</u>
As per Guy Lussac's law, the pressure of any concealed volume of gas particles will be directly proportional to the temperature of the container of the gas particles.
So P ∝ T
To convert celsius to kelvin, add 273.15 to the temperature value in celsius
Since, here the initial temperature of the flask is given as 24°C, so in kelvin it will be 297.15 K. Similarly, the final temperature is said to be 104°C which will be equal to 377.15 K. Then the final pressure will be increased as there is increase in temperature. So, the final pressure inside the flask can be obtained as


So, the pressure inside the flask on heating it is given as 1.21 atm.
M of water = 2(1) + 16 = 18 g/mol
n of water = 24g/(18g/mol) = 4/3 mol
n of H2O : n of O2 = 2 : 1
2:1 = 4/3 : x
x = (4/3)/2 = 2/3 mol of O2