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3 years ago

How many unpaired electrons are present in the ground state of the atoms in group 6a(16)?

1 answer:

5 0

Lets take one element from Group 6A, Let it be oxygen, The electronic configuration of Oxygen is as follow,

O = 8 = 1s², 2s², 2px², 2py¹, 2px¹

There are 6 electrons in the valence shell of elements present in Group 6A. The unpaired electrons in 2px and 2py are involved in forming covalent bond, while the pair of electrons in 2s and 2px are unshared and act as lone pair of electrons.

Result:
There are TWO unpaired electrons present in the ground state of Group 6A elements.

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4Cr(s)+3O2 (g )= Cr2O3 (s) Find the theoretical yield in moles and grams

Assoli18 [71]

The balanced reaction is:

4Cr(s)+3O2 (g )= Cr2O3 (s)

Since we are not given the amount of any of the reactants, we assume we have one gram of chromium. Calculations are as follows:

1 g Cr ( 1 mol Cr / 52 g Cr ) ( 1 mol Cr2O3 / 4 mol Cr ) = 0.005 mol Cr2O3

0.005 mol Cr2O3 (151.99 g Cr2O3 / 1 mol Cr2O3 ) = 0.7307 g Cr2O3

Therefore, the theoretical yield for 1 gram of Cr is 0.005 mol Cr2O3 or 0.7307 g Cr2O3.

7 0

3 years ago

If you combine 230.0 mL 230.0 mL of water at 25.00 ∘ C 25.00 ∘C and 120.0 mL 120.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is t

Thepotemich [5.8K]

Answer: The final temperature of the mixture is 49°C

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

For cold water:

Density of cold water = 1 g/mL

Volume of cold water = 230.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{230.0mL}\\\\\text{Mass of water}=(1g/mL\times 230.0mL)=230g$

For hot water:

Density of hot water = 1 g/mL

Volume of hot water = 120.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{120.0mL}\\\\\text{Mass of water}=(1g/mL\times 120.0mL)=120g$

When hot water is mixed with cold water, the amount of heat released by hot water will be equal to the amount of heat absorbed by cold water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of hot water = 120 g

$m_2$ = mass of cold water = 230 g

$T_{final}$ = final temperature = ?°C

$T_1$ = initial temperature of hot water = 95°C

$T_2$ = initial temperature of cold water = 25°C

c = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$120\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]$

$T_{final}=49^oC$

Hence, the final temperature of the mixture is 49°C

4 0

4 years ago

What's the valency of lead in pbO2

Andru [333]

The valence of lead is 4.

Hence the name of the compound is called Lead (IV) oxide.

<h3>Further explanation</h3>

Given

PbO₂ compound

Required

The valence of Pb

Solution

The oxidation number of element O in the compound = -2, except for OF₂ the oxidation state = + 2 and the peroxides (Na₂O₂, BaO₂) the oxidation state = -1 and superoxide, for example KO₂ = -1/2.

The oxidation state in the uncharged compound = 0,

So The oxidation state of Pb :

Pb + 2.(-2) = 0

Pb - 4 = 0

Pb = +4

8 0

3 years ago

The ----------------- cells, make up the upper and lower layers of the leaf.

Nataly [62]

Answer:

epidermal! hope this helps u!

4 0

3 years ago

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Peter performed an experiment to test which of the three compounds his teacher gave him was an ionic compound. The table shows h

Irina18 [472]

Answer:B is an ionic compound

Explanation:This is because when we look at the properties of ionic compounds, we see that the form crystals just like salt(sodium chloride), they dissolve in water, have a high boiling and melting point, are hard due to the strong intermolecular forces between atoms and conduct electricity (only molten or in solution form)

5 0

4 years ago

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