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3 years ago

Is a triangle with side lengths 8 in, 12 in, and 14 in a right triangle? explain

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

6 0

Its 17 15 and 8 i just did that on a test as well
srry no explanation :(

Harman [31]3 years ago

6 0

No because a right triangle has at least one side that measures 90°

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Which graph shows the system 1 x² + y = 2 x² + y² = 9

BartSMP [9]

Answer:

The graph of the system in the attached figure

Step-by-step explanation:

we have

$x^{2}+y=2$

isolate the variable y

$y=-x^{2}+2$ ----> equation A

This is the equation of a vertical parabola open down (because the leading coefficient is negative)

The vertex represent a maximum

the vertex is the point (0,2)

$x^{2} +y^{2}=9$ ---> equation B

This is the equation of a circle centered at (0,0) with radius 3 units

The solution of the system of equations is the intersection points both graphs

using a graphing tool

The solutions are the points (-2.05,-2.19) and (2.05,-2.19)

see the attached figure

5 0

3 years ago

Bearings Problem Solving Question:

Lynna [10]

9514 1404 393

Answer:

a) 123.4°

b) 3.3 km

Step-by-step explanation:

In (N, E) coordinates, Boat 1 is located relative to the lighthouse at ...

2(cos(60°), sin(60°)) = (1.0, 1.732) . . . . . km

Boat 2 is located at ...

3(cost(340°), sin(340°)) = (2.819, -1.026) . . . . . km

So, relative to Boat 2, Boat 1 is located at ...

(1, 1.732) -(2.819, -1.026) = (-1.819, 2.758) . . . . . km

This is at a bearing of ...

arctan(2.758/-1.819) = 123.4°

and a distance of ...

√(1.819² +2.758²) ≈ 3.304 . . . . . km

a) Boat 2 would need to travel on a bearing of 123.4°.

b) Boat 2 would need to travel 3.3 km.

_____

Additional comment

We use (North, East) coordinates so we don't have to do the mental gyrations necessary to translate to and from (E, N) coordinates. The latter would correctly orient a map relative to the X-Y Cartesian plane. The former are equivalent to flipping the map over and looking at it from the back side. This is a "rigid transformation", so angles and distances remain unchanged.