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2 years ago

How do I write 55555 in expanded form

Mathematics

2 answers:

marta [7]2 years ago

7 0

Answer:

FIFTY - FIVE THOUSAND FIVE HUNDRED AND FIFTY-FIVE

Step-by-step explanation:

WITCHER [35]2 years ago

6 0

5 ten thousands + 5 thousands + 5 hundreds + 5 tens + 5 ones

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Can someone pls help with these geometry questions, it’s urgent.

Phantasy [73]

Answer:

6. x + x + 14 = 90

2x + 14 = 90

2x = 76

x = 38

angle b = 38 + 14 = 52°

7. angles on a straight line add up to 180°

x + x - 32 = 180

2x = 212

x = 106°

angle d = 106 - 32 = 74°

8. vertically opposite angles are equal

7x - 80 = 3x

-80 = -4x

20 = x

angle 1 = 7(20) - 80 = 60°

angle 2 = 3(20) = 60°

7 0

2 years ago

Jasmine created this spinner to predict whether a randomly selected student in her school will be traveling during the upcoming

riadik2000 [5.3K]

Answer: 9

Step-by-step explanation:

There are 8 equal sections which are meant to reflect the data Jasmine collected from surveying the students.

This means that each section represents;

= 36/8

= 4.5 students.

There are 2 sections that represent the number of students who said they would be traveling during the holiday break.

= 4.5 * 2

= 9 students

4 0

2 years ago

Read 2 more answers

Factor the four-term polynomial ab + ac - 4b - 4c

Troyanec [42]

A b + a c - 4 b - 4 c = a ( b + c ) - 4 ( b + c ) =
= (b + c) (a - 4)

5 0

2 years ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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2 years ago

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Yo if u need an bralest i got chu

dybincka [34]

Answer:

PLease

Step-by-step explanation:

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3 years ago

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