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adell [148]
3 years ago
8

Pauline Found​ Manufacturing, Inc., is moving to kanbans to support its telephone​ switching-board assembly lines. Determine the

size of the kanban for subassemblies and the number of kanbans needed. Setup cost ​$30 Annual holding cost ​$125 per subassembly Daily production 25 subassemblies Annual usage 4 comma 000 ​(50 weeks times 5 days each timesdaily usage of 16 ​subassemblies) Lead time 10 days Safety stock 2 ​days' production Kanban container size​ = nothing units ​(round your response to the nearest whole​ number).
Business
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

Kanban container size = 73

Number of kanbans needed = 5

Explanation:

Kanban container size (Q):

Q = SQRT [(2 x D x S) / H x (1 - d/p)]

where,

D = Annual demand  

S = Setup cost

H = Holding cost

d = Daily usage

p = Daily production

Putting the given values in the above formula,

CONTAINER SIZE = SQRT ((2 * ANNUAL DEMAND * SETUP COST) / (HOLDING COST * (1 - (DAILY USAGE / DAILY PRODUCTION))))

Q = SQRT [(2 x 4,000 x $30) / $125 x (1 - 16/25)]

Kanbans container size = 73 units  (Rounding off to the nearest whole number)

NUMBER OF KANBANS = DEMAND DURING LEAD TIME + SAFETY STOCK / SIZE OF CONTAINER

K = ((16 * 16) + (4 * 25) / 73 = 5

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3 years ago
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Using the attached sheet (or a spreadsheet if you prefer), prepare a classified balance sheet for the ABC, LLC for the year ende
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Answer:

ABC, LLC

Classified balance sheet as at December 31, 2020

                                                                                              $

ASSETS

Non - Current Assets

Land                                                                                 25,000

Total Non - Current Assets                                             25,000

Current Assets

Accounts Receivable                                                        3,000

Cash                                                                                 20,000

Total Current Assets                                                       23,000

TOTAL ASSETS                                                               48,000

EQUITY AND LIABILITIES

LIABILITIES

Non - Current Liabilities

Notes Payable (due in 5 years)                                      10,000

Total Non - Current Liabilities                                        10,000

Current Liabilities

Accounts Payable                                                            4,000

Salaries Payable                                                              5,000

Total Current Liabilities                                                   9,000

TOTAL LIABILITIES                                                         19000

EQUITY

Common Stock                                                                1,000

Preferred Stock                                                               8,000

Treasury Stock                                                                6,000

Retained Earnings                                                          7,000

Paid in Capital in Excess of Par - Common Stock       17,000

Paid in Capital in Excess of Par - Preferred Stock       2,000

TOTAL EQUITY                                                              41,000

TOTAL EQUITY AND LIABILITIES                                60,000  

Explanation:

A classified balance sheet shows the Assets, Liability and Equity Balances in their respective categories as shown above.

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Answer:

The probability that 2 or 3 customers will arrive in a 15-minute period is 0.4703

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Firstly, we have to determine the segment unit, since the mean is 10 per hour, the segment unit is 1 hour.

The mean(m) = 10

since the period is 15 minutes = 0.25 hour, t= 0.25 hour / 1 hour. Therefore mt= 2*10 = 2.5

The poisson distribution formula P(x) = \frac{(mt)^{x}e^{-mt}  }{x!}

Therefore the probability that 2 or 3 customers will arrive in a 15-minute period

P(x=2) or P(x=3) = P(x=2) + P(x=3) = \frac{(2.5)^{2}e^{-2.5}  }{2!}+\frac{(2.5)^{3}e^{-2.5}  }{3!} = 0.2565 + 0.2138 = 0.4703

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(a) requires that individual employees be specifically named.

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Assume that Schmidt Machinery Company had the standard costs reflected in Exhibit 14.5. In a given month, the company used 3,530
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Answer:

price variance  $14,040 U

quantity variance  $ 5,650  F

rate variance          $  10,700  U

efficiency variance  $ 26,800 U

Explanation:

Missing information attached:

Purchase of Aluminium:

66 ending + 3,530 used - 46 beginning = 3,510

DIRECT MATERIALS VARIANCES

(standard\:cost-actual\:cost) \times actual \: quantity= DM \: price \: variance

std cost         $25.00

actual cost  $29.00

quantity             3,510 (purchase)

difference  $(4.00)

price variance  $(14,040.00)

(standard\:quantity-actual\:quantity) \times standard \: cost = DM \: quantity \: variance

std quantity             3756.00 (939 units x 4 pounds per unit)

actual quantity     3530.00

std cost                       $25.00

difference               226.00

quantity variance  $5,650.00

DIRECT LABOR VARIANCES

(standard\:rate-actual\:rate) \times actual \: hours = DL \: rate \: variance

std rate          $40.00

actual rate  $42.00

actual hours 5,350

difference  $(2.00)

rate variance  $(10,700.00)

(standard\:hours-actual\:hours) \times standard \: rate = DL \: efficiency \: variance

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actual hours 5350.00

std rate  $40.00

difference -670.00

efficiency variance  $(26,800.00)

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