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xxMikexx [17]
4 years ago
9

Helppppppppppppppppppp

Mathematics
1 answer:
Crank4 years ago
6 0
\boxed{a_1=0.2}\\\\\\r=\dfrac{-0.06}{0.2}=\boxed{-0.3}

so:

a_n=a_1(r)^{(n-1)}\\\\\boxed{a_n=0.2(-0.3)^{(n-1)}}

Answer E.
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