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3 years ago

Helppppppppppppppppppp

Mathematics

1 answer:

Crank3 years ago

6 0

$\boxed{a_1=0.2}\\\\\\r=\dfrac{-0.06}{0.2}=\boxed{-0.3}$

so:

$a_n=a_1(r)^{(n-1)}\\\\\boxed{a_n=0.2(-0.3)^{(n-1)}}$

Answer E.

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Please help me! I think this 20 character thing is unnecessary when you have an attachment

PIT_PIT [208]

Answer:

Step-by-step explanation:

Also the answer must be under 9 so that rules out option D

Because We know CE = 2 and AD is visibly larger than CE, 6We can rule out option A

And that brings us down to B and C

CB is equal to 6, And I'm no genius, but I'm pretty sure AD is DEFINATLY not equal to 6.

so the answer is B

8 0

3 years ago

Find the area and perimeter.<br> The area is ... and the perimeter is ...

Schach [20]

Answer:

Area: 6a^2

Perimeter: 12a^2

Step-by-step explanation:

To find the area of a triangle, use the formula A=1/2 b*h. The base is 3a^2 and the height is 4a^2.

A= 1/2 (3a^2)(4a^2)

A = 1/2 (12a^4)

A = 6a^4

To find the perimeter of the triangle, add each of the sides of the triangle. The third side, the hypotenuse, can be found using Pythagorean theorem.

$a^2+b^2=c^2\\(3a^2)^2+(4a^2)^2 = c^2\\(9a^4)+(16a^4)=c^2\\25a^4=c^2\\5a^2=c$

Now add each of the sides: 3a^2 + 4a^2 +5a^2 = 12a^2

7 0

4 years ago

PLEASE HELP ME WITH THIS THANKS

Zarrin [17]

Answer:

The answer to your question is SA = 2419.34 m²

Step-by-step explanation:

Data

a = 11.42 m

side = 11 m

height = 20 m

Formula

SA = 2B + PH

Process

1.- Calculate P

Perimeter = P

P = 7(11)

= 77 m

2.- Calculate B

B = Pa/2

= (77)(11.42)/2

= 879.34/2

= 439.67 m²

3.- Calculate 2B

2B = 2(439.67)

= 879.34 m²

4.- Calculate PH

PH = (77)(20)

= 1540 m²

5.- Calculate SA

SA = 879.34 + 1540

= 2419.34 m²

4 0

3 years ago

Read 2 more answers

The function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237. Find the a

trapecia [35]

Answer:

29 is answer.

Step-by-step explanation:

Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.

To find average velocity of the object over the interval of time [1,3]

We know that derivative of s is velocity and antiderivative of velocity is position vector .

Since moving along a line equation of s is

use two point formula

$\frac{s-150}{237-150} =\frac{t-2}{5-2} \\s=29t-58+150\\s=29t+92$ gives the position at time t.

Average velocity in interval (1,3)

= $\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29$

5 0

3 years ago

(-9)4 what is (-9) to the power of for is

Luba_88 [7]

Answer:

6,561

Step-by-step explanation:

(-9)^4 = -9*-9*-9*-9= 6,561

8 0

4 years ago