Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)
sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)
cos(α) = adjacent/hypotenuse
= 1/sqrt(3)
now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math
The Second one hope it helped
$10+$5=15
$75/$15=5
Hours = 5
Is this what you were looking for?
This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.
To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.
The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:
4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13
This is the answer you are looking for. I hope this helps :)
Step-by-step explanation:
mean is always equal to additon of total no.s by total no.s
2 + 4 + 6 + 8 + 10 + 12
=42
total no.s = 6 no.s
42/6
=7
therefore 7 is the answer which is the mean deviation of the following no.s .
