Using the discrete probability outputs given in the attached table ; the probability values of having exactly 6 ; and having 6 or more girls are :
<u>The </u><u>probability</u><u> of having </u><u>exactly 6 girls</u><u> can be defined as</u> :
- P(X = 6) = 0.111 (from the discrete probability table)
2.)
<u>The </u><u>probability</u><u> of having </u><u>6 or more</u><u> girls can be defined as</u> :
- P(X ≥ 6) = P(X = 6) + P(X = 7) + P(X = 8)
- From the table attached :
- P(X ≥ 6) = 0.111 + 0.014 + 0.003 = 0.1
Therefore, the probability of having exactly 6 girls is 0.111 while the probability of having 6 or more girls is 0.1
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Step-by-step answer:
Let's attack the left side:
log_8 12 = log (base 8) 12 = log(12)/log(8) = 1.1949875 (approx.)
Next solve
log_8 12 = x-2
log(12)/log(8) = x-2
x = 2 + log(12)/log(8)
= 3.195 (to one thousandth)
Answer:
Sum of interior angles of polygon = (n-2)*180
1) Pentagon:
2)Hexagon:
3) Heptagon:
4) Octagon:
Answer:
6
h
+
2
y
+
4 is your answer
Step-by-step explanation:
Hope this helps! :)
27, 36, 45
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