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Makovka662 [10]
2 years ago
10

A widow's peak is a V-shaped area of the hairline in the center of the forehead. The allele for having a widow's peak is dominan

t to the allele for not having a widow's peak.
If two parents do not have widow's peaks, what is the probability that their child will have a widow's peak?
Chemistry
2 answers:
Flauer [41]2 years ago
8 0
<span>None. Since it is dominant, both would have to show it to pass in on.</span>
Aleonysh [2.5K]2 years ago
7 0

Answer:

0%

Explanation:

A widow's peak is a V-shaped point in the hairline in the center of the forehead. Hair growth on the forehead is suppressed in a bilateral pair of periorbital fields. Without a widow's peak, these fields join in the middle of the forehead so as to give a hairline that runs straight across.

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These statements describe three different reactions.
Naily [24]

An atom gains an electron from another atom. Hence, option B is the correct answer.

<h3>What is an atom?</h3>

An atom is a particle of matter that uniquely defines a chemical element. An atom consists of a central nucleus that is usually surrounded by one or more electrons.

When an atom shares electrons with another atom then it results in the formation of a covalent bond.

Whereas when an atom transfer electrons from one atom to another then it results in the formation of an ionic bond.

When the nucleus of an atom splits then it represents a nuclear fission reaction and energy is released during this process.

Hence, option B is the correct answer.

Learn more about the atom here:

brainly.com/question/1566330

#SPJ1

5 0
1 year ago
Can anyone help me on this please?
Bad White [126]
This question is testing to see how well you understand the "half-life" of radioactive elements, and how well you can manipulate and dance around them.  This is not an easy question.

The idea is that the "half-life" is a certain amount of time.  It's the time it takes for 'half' of the atoms in any sample of that particular unstable element to 'decay' ... their nuclei die, fall apart, and turn into nuclei of other elements.

Look over the table.  There are 4,500 atoms of this radioactive substance when the time is 12,000 seconds, and there are 2,250 atoms of it left when the time is ' y ' seconds.  Gosh ... 2,250 is exactly half of 4,500 !  So the length of time from 12,000 seconds until ' y ' is the half life of this substance !  But how can we find the length of the half-life ? ? ?

Maybe we can figure it out from other information in the table !

Here's what I found:

Do you see the time when there were 3,600 atoms of it ? 
That's 20,000 seconds.

... After one half-life, there were 1,800 atoms left.
... After another half-life, there were 900 atoms left.
... After another half-life, there were 450 atoms left. 

==>  450 is in the table !  That's at 95,000 seconds.

So the length of time from 20,000 seconds until 95,000 seconds
is three half-lifes.

The length of time is (95,000 - 20,000) = 75,000 sec

                                     3 half lifes = 75,000 sec

Divide each side by 3 :   1 half life = 25,000 seconds

There it is !  THAT's the number we need.  We can answer the question now.

==> 2,250 atoms is half of 4,500 atoms.

==> ' y ' is one half-life later than 12,000 seconds

==> ' y ' = 12,000 + 25,000

         y   = 37,000 seconds  .

Check: 
Look how nicely 37,000sec fits in between 20,000 and 60,000 in the table.

As I said earlier, this is not the simplest half-life problem I've seen.
You really have to know what you're doing on this one.  You can't
bluff through it.


7 0
3 years ago
True or false. elements in the same period have the same number of valence electrons
saul85 [17]
False. elements in the same period have the same number of shells while elements in the same group have the same number of valence electrons.
4 0
3 years ago
How many liters of O2 at 298 K and 1.00 bar are produced in 1.50 hr in an electrolytic cell operating at a current of 0.0200 A?
stellarik [79]

Answer: 0.0069L

Explanation:

2H2O(l) ---->O2(g) + 4H+(aq) + 4e-

no of moles= it/eF

NO of moles of O2 produced = (Current in Ampere x Time in second)/ (Faraday constant x Number of electrons required)

Moles of O2 produced = (0.02x (60 x 60X1.5 s)/(96485 x 4)

= 0.0002798 moles= 2.798x 10 ^-4moles

Using  ideal gas equation,

P V = n R T

Where, P is the pressure,

V is the volume,

n is the number of moles,

R is the gas constant, and T is the temperature

We have, 1 bar = 0.986923 atm

Substituting the values,

V = nRT/P = (2.798 x 10-4moles x 0.08205 L atm mol K x 298 K)/ 0.986923 atm = 0.0069L

Volume of O2 produced = 0.0069L

7 0
3 years ago
An unknown mass of aluminum requires 6290 joules to raise the tempature from 23.9 degrees c to 80.0 degrees c what is the Mass o
Katyanochek1 [597]
Answer: the mass of aluminum is 124.579 g

7 0
2 years ago
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