We are given the equation 3CO(g) + Fe2O3(s)= Fe(s) + 3CO2(g) and determine the next step in balancing the equation. In this case,C is already balanced. The next step is to balance Fe so we put 2 before Fe (s) to balance the 2 atoms in the left of the equation.
<h3>
Answer:</h3>
- Balanced Equation; 2Fe + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂
- Why balance?: To obey the law of conservation of mass
- Subscripts can not be changed, since they show the actual number of atoms of each element in a compound.
<h3>
Explanation:</h3>
- The balanced equation for the reaction between the iron metal and sulfuric acid to produces iron (III) sulfate and hydrogen gas is given by;
2Fe + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂
- Balancing chemical equations ensures that they obey the law of conservation of mass which requires the mass of reactants and the mass of products to be equal.
- Balancing is done by putting coefficients on reactants and products while not affecting the subscripts as subscripts show the actual number of atoms of an element in a compound.
The question is basically asking what is happening to the energy (that is in the form of heat) when it is being absorbed by an object. The energy being absorbed from the heat source is being turned into kinetic energy. This can be explained by temperature change. As you add more heat to an object, the temperature rises. Since temperature is the average kinetic energy of all of the molecules in an object, we can say that as temperature rises so does the kinetic energy of the molecules in the object. Due to the fact that heat is causing the temperature to increase, we can say that the energy from the heat is being turned into kinetic energy.
I hope this helps. Let me know in the comments if anything is unclear.
Answer:
-179.06 kJ
Explanation:
Let's consider the following balanced reaction.
HCl(g) + NaOH(s) ⟶ NaCl(s) + H₂O(l)
We can calculate the standard enthalpy change for the reaction (ΔH°r) using the following expression.
ΔH°r = 1 mol × ΔH°f(NaCl(s)) + 1 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(NaOH(s))
ΔH°r = 1 mol × (-411.15 kJ/mol) + 1 mol × (-285.83 kJ/mol) - 1 mol × (-92.31 kJ/mol) - 1 mol × (-425.61 kJ/mol)
ΔH°r = -179.06 kJ
Answer:
The number of mol is: 0, 042 mol in 4 grams of MgCl2
Explanation:
We calculate the weight of 1 mol of MgCl2:
Weight 1mol of MgCl2= weight Mg + (weight Cl)x 2=
24, 3 grams + 2 x 35, 5 grams = 95, 3 grams/mol MgCl2
95, 3 grams------1 mol MgCl2
4 grams -------x = (4 grams x1 mol MgCl2)/ 95, 3 grams= 0, 04197 mol MgCl2
