<em>Answer:</em>
<em>B.) A hot liquid or air that expands, becomes less dense, and rises or becomes more dense and sinks.</em>
<em>Explanation:</em>
<em>Convention is the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.</em>
1 μL = 10^-6 L by definition
So...
82 μL = 82x10^-6 L = 8.2x10^-5 L
If we have in mind the following procedure:
BACo3(s) + H +1 -> Ba +2 + HCO3 -1
CO3 - 2 + H+1 -> HCO3 -1
As nitric acid is added then {CO3 -2 } decreases meaning that more BaCo3 can dissolve. The graph you need to use is the one that the curve goes down and closer to solubility and goes up on conc.
First find the molar masses of all of the compounds:
SrCl2 = 158.53g/mol
SrI2 = 341.43g/mol
SrO = 103.62g/mol
SrS = 119.68g/mo
Then find the molar mass of Sr in each of the compounds. Since there is only one Sr in every compound, the mass will be the same: 87.62g/mol Sr
Now divide the molar mass of Sr by each of compounds' masses:
SrCl2 = (87.62)/(158.53) = 0.553
SrI2 = (87.62)/(341.43) = 0.257
SrO = (87.62)/(103.62) = 0.846
SrS = (87.62)/(119.68) = 0.732
Now multiply each of the results by 100 to get the percent composition of Sr by mass:
(0.553)(100) = 55.3% Sr in SrCl2
(0.257)(100) = 25.7% Sr in SrI2
(0.846)(100) = 84.6% Sr in SrO
(0.732)(100) = 73.2% Sr in SrS
Thus SrO has the highest percent composition by mass of Sr
<u>Answer:</u> The molar mass of unknown gas is 367.12 g/mol
<u>Explanation:</u>
Rate of a gas is defined as the amount of gas displaced in a given amount of time.
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:
So,
We are given:
Volume of unknown gas (X) = 1.0 L
Volume of oxygen gas = 1.0 L
Time taken by unknown gas (X) = 105 seconds
Time taken by oxygen gas = 31 seconds
Molar mass of oxygen gas = 32 g/mol
Molar mass of unknown gas (X) = ? g/mol
Putting values in above equation, we get:
Hence, the molar mass of unknown gas is 367.12 g/mol
