The function that models exponential growth is:
P(t) = P0*(1 + r)^t, where
P0 = P(0) is the initial value of P
r is the growth rate as a decimal
In our case we have:
P(0) = 2800
r = 0.035 or 3.5%
P(t) = 2800*(1 + 0.035)^t
P(t) = 2800*(1.035)^t
The same exponential function written using y and t is:
y = 2800*1.035^t.
Explanation: https://softmath.com/algebra-word-problems/to-begin-a-bacteria-study-a-petri-dish-had-2800-bacteria
Answer:
59 to 66
Step-by-step explanation:
Mean test scores = u = 74.2
Standard Deviation =
= 9.6
According to the given data, following is the range of grades:
Grade A: 85% to 100%
Grade B: 55% to 85%
Grade C: 19% to 55%
Grade D: 6% to 19%
Grade F: 0% to 6%
So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.
6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)
The formula for z score is:

For z = -1.56, we get:

For z = -0.88, we get:

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)
53.35/11 = 4.85 for 1 key chain
4.85 *4 = 19.40
We have,

Introduce variable
such that 
The sum
is therefore 
So,
(sadia's age)
(father's age)
Hope this helps :)
Answer:
y=-1/5x-1
Step-by-step explanation: