Write the amount as a fraction of a dollar, as a decimal, and as a money amount.
2 answers:
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Notice* No options are provided, so I will solve the expression.
Answer:
Step-by-step explanation:
Step 1: Simplify
Step 2: Rewriting the whole as an Equivalent Fraction
Subtracting a fraction from a whole
Rewrite the whole as a fraction using 5 as the denominator :
5x = 5x/1 = 5x * 5/5
<em>Equivalent fraction</em> : The fraction thus generated looks different but has the same value as the whole
<em>Common denominator </em>: The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
dding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
5x • 5 - (4) 25x - 4
-------------- = ---------
5 5
Step 3: Simplify 25/4
Rewriting the whole as an Equivalent Fraction :
Adding a whole to a fraction
Rewrite the whole as a fraction using 4 as the denominator :
29 = 29/1 = 29 * 4/4
Adding fractions that have a common denominator :
Adding up the two equivalent fractions
5 • (25x-4) + 29 • 4 125x + 96
--------------------------- = -----------
4 4
Final result :
125x + 96
—————————
4
___________
Terms and topics:
- Dividing exponents
- Polynomial roots
- Nonlinear equations
- Equations which are reducible to quadratic
- Reducing fractions to lowest terms
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.
The standard deviation is a measure of dispersion obatined from the sample variance and is given by:
Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.