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Lera25 [3.4K]
3 years ago
7

What is the point slope equation of the line with slope 5 that passes through (2,-3)

Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:12

Step-by-step explanation:

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Slope of 1,-7 and -3-4​
3241004551 [841]

\large \mathfrak{Solution : }

Slope of the given line is :

  • \dfrac{y_2 - y_1}{x_2 - x_1}

where ,

  • x_2 = 1

  • x_1 =  - 3

  • y_2 =  - 7

  • y_1 =   - 4

let's solve :

  • \dfrac{ - 7 - ( - 4)}{1 - ( - 3)}

  • \dfrac{ - 3}{4}

Slope = -3 / 4

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2 years ago
For cones with radius 6 units, the equation V = 127th relates the height h of the cone, in units, and the volume V of the cone,
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Answer:

hola

Step-by-step explanation:

cómo estás yo bien compita

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2 years ago
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Explain how to calculate the surface area of a composite figure in your own words.
AleksAgata [21]
To calculate the <span>surface area of a composite figure you must apply the formulas for calculate the area of each figure that is part of the composite figure and then, you must sum all the areas calculated.

 For example, is the composite figure is form by a triangle and rectangle, the surface area of the composite figure will be:

 SA= Area of the triangle+ Area of the rectangle= (bh/2)+bh</span>
8 0
3 years ago
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Which is the best buy?<br> Pack of 8 apples for £1.65<br> Pack of 6 apples for £1.25
Sliva [168]

Answer:

Pack of 6 apples for £1.65 is better because the price of 1 apple is less in this answer.

7 0
2 years ago
Please help if you can pic attatched
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

CI=\left[\begin{array}{ccc}1&6&0\\0&1&2\\1&-1&3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]

Subtract row 3 from row 1:

\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&7&-3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\1&0&-1\end{array}\right]

Subtract row 3 from 7 times row 2:

\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&17\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\-1&7&1\end{array}\right]

Divide row 3 by 17:

\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]

Subtract 2 of row 3 from row 2:

\left[\begin{array}{ccc}1&6&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]

Subtract 6 of row 2 from row 1:

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}\frac{5}{17}&\frac{-18}{17}&\frac{12}{17}\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]

C^{-1}=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]

C^{-1}b=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]\left[\begin{array}{c}10&1&3\end{array}\right]=\left[\begin{array}{c}4&1&0\end{array}\right]

3 0
3 years ago
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